python - Pygame 中的屏幕输入

Question

对于学校的一个编程项目，我必须使用 pygame 创建一个拼写游戏。但是，由于我对这整件事还很陌生，所以我无法弄清楚如何让用户输入字母并使它们出现在游戏显示屏上。到目前为止，这是我的代码(以及我尝试解决此问题的失败尝试):

import pygame
import random

pygame.init()

display_width = 800
display_height = 600

black = (0,0,0)
white = (255,255,255)
red = (255,0,0)

gameDisplay = pygame.display.set_mode((display_width,display_height))
pygame.display.set_caption("Spelling Game")
myfont = pygame.font.SysFont("Arial", 50)
clock = pygame.time.Clock()
mouse = pygame.mouse.get_pos()

city = pygame.image.load("city.png")

charac_str = ""  #new string to store written character
# font object to render str to surface
font_renderer = pygame.font.SysFont("Arial",30)

def background(x,y):
    gameDisplay.blit(city,(-200,-100))

with open("words.txt") as f:
    WORDS = f.read().split()

def random_word():
    return random.choice(WORDS) 


gameExit = False
word = random_word()

while not gameExit:
    #event-handling loop based on user input
    for event in pygame.event.get():
        if event.type == pygame.QUIT:            
            pygame.quit()
            quit() 

    gameDisplay.fill(white)

    background(0,0)
    textsurface = myfont.render(word, True, red)
    gameDisplay.blit(textsurface, (340, 400))     #the random word

    rendered_charac = font_renderer.render(charac_str, True, red)
    gameDisplay.blit(rendered_charac, (100,100))

    pygame.display.update()

    for event in pygame.event.get():
        if event.type == pygame.KEYDOWN:
            if pygame.K_0 < event.key < pygame.K_9: #checks key pressed
                character = chr(event.key) #conv num to char
                charac_str += str(character) # add num to end of string
                gameDisplay.blit(charac_str) # display the input?doesn't work

Answer 1

pygame.KEYDOWN 事件有一个 unicode 属性，您可以简单地将其添加到字符串中，例如text += event.unicode。然后在主循环中渲染并显示文本。

import pygame as pg


def main():
    screen = pg.display.set_mode((640, 480))
    font = pg.font.Font(None, 32)
    clock = pg.time.Clock()
    color = pg.Color('dodgerblue2')
    text = ''

    while True:
        for event in pg.event.get():
            if event.type == pg.QUIT:
                return
            elif event.type == pg.KEYDOWN:
                if event.key == pg.K_RETURN:
                    print(text)
                    text = ''
                elif event.key == pg.K_BACKSPACE:
                    text = text[:-1]
                else:
                    text += event.unicode

        screen.fill((30, 30, 30))
        txt_surface = font.render(text, True, color)
        screen.blit(txt_surface, (50, 100))

        pg.display.flip()
        clock.tick(30)


if __name__ == '__main__':
    pg.init()
    main()
    pg.quit()