c - 使用字符串查找数字平均值

Question

作为学习练习，我正在创建一个程序，将通过 argv[1] 输入的字符转换为整数。该程序然后找到整数的数字平均值。

例如:abc 将是 123，并且 1+2+3 = 6，其中 6 是数字平均值。该程序的第一部分可以运行，但我无法正确编码找到数字平均值的部分。

word abc 的输出应该是 123 6；相反，它是 123 150。

---

编辑:已解决!

#include <stdio.h>
#include <strings.h>

int main(int argc, char *argv[])
{
    char stra[27], strb[0];
    int str_num, str_len;
    int final = 0;

    if (argv[1][0] < 'a')
    {
        printf("!Argument missing!");
        return 0;
    }

    strcpy(stra, argv[1]);
    str_len = strlen(stra);

    for (str_num = 0; str_num < str_len; str_num++)
    {
        if (stra[str_num] <= 'z' && stra[str_num] >= 'a')
        {
            strb[str_num] = (stra[str_num] - 'a' + 1) % 9 + '0';
            if (strb[str_num] == '0')
            {
                strb[str_num] = '9';
            }
        }
        else
        {
            printf("%s !Please use only the lower case!", stra);
            return 0;
        }
    }

    for (str_num = 0; str_num < str_len; str_num++)
    {
        final += strb[str_num] - '0';
    }

    printf("%s %i", strb, final);
    return 0;
}

Answer 1

#include <stdio.h>
#include <strings.h>
int main(int argc, char *argv[])
{
    char *stra;
    char *strb;
    int str_num;
    int str_len;
    int final;
    final = 0;
    if ( (argc >= 2 && argv[1][0] < 'a') || (argc <= 1))
    {
        printf("!Argument missing!");
        return 0;
    }
    str_len = strlen(argv[1]);

    strb = (char*) malloc((str_len+1)*sizeof(char));

    for (str_num = 0; str_num < str_len; str_num++)
    {
        if (argv[1][str_num] <= 'z' && argv[1][str_num] >= 'a')
    {
        strb[str_num] = (argv[1][str_num] - 'a'+1) % 9 + '0'; //to get string with numbers from 1 to 9
        }
        else
        {
            printf("%s !Please use only the lower case!",argv[1]);
            return 0;
        }
    }
    strb[str_len] = '\0' // put the end char of the string : mandatory to print it.
    for (str_num = 0; str_num < str_len; str_num++)
    {
        final += strb[str_num] - '0';  // count the sum of the numbers from 1 to 9 ?
    }
    printf("%s %i",strb,final);
    free(strb);
    return 0;
}