python - 如何检查变量是否包含不允许输入的字符？

Question

我正在编写一个密码程序，如果满足某些要求，它将显示一个分数。但我坚持如何检查是否不允许使用某些字符。如果不允许，则应通知读者。这是我的代码:

user_password = input("\nEnter your password:")
user_score = 0
user_length = len(user_password)
symbols = "$%^&*()_-+="

if len(user_password)>24:
    print("Your password is too long! It must be between 6 and 24")
elif len(user_password)<6:
    print("Your password is too short! It must be between 6 and 24")
elif len(user_password) >=6 and len(user_password) <= 24:
    lower = sum([int(c.islower()) for c in user_password])
    if lower > 0:
            user_score = user_score + 5
    upper = sum([int(c.isupper()) for c in user_password])
    if upper > 0:
            user_score = user_score + 5
    integer = sum([int(c.isdigit()) for c  in user_password])
    if integer > 0:
            user_score = user_score + 5
    for c in symbols:
            if c in user_password:
                    user_score = user_score + 5
    for c in user_password:
            if c not in symbols:
                    print("Some symbols you entered are not allowed")
                    break

我想要这样，如果输入错误的符号，程序就会结束。但是，当输入错误的符号时，它会显示该符号输入次数的消息。任何帮助将不胜感激。

Answer 1

您需要更改最后一个 for-loop 以使其失败 if c in symbols，您在其中有一个 not放弃程序...

for c in user_password:
            if c in symbols:
                    print("Some symbols you entered are not allowed")
                    break

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仅使用 2``行 的更短方法是使用 any:

if any(c in symbols for c in user_password):
            print("Some symbols you entered are not allowed")

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最后要注意的是，为了可读性，您应该尽量将缩进 的宽度保持在恒定的4 空格。我没有在这些片段中这样做，因为您将能够使用现有代码测试它们，但理想情况下您应该更改它们。