c - 如何解释用户输入的字符串？

Question

int main()
{
printf("Welcome to the temperature control program:\n");
    printf("enter the ascii temperature characters");
    printf("enter the ascii characters of an euipment name with + or - and followed by a integer value");
    printf("type character terminated by carriage return");

    char tbuffer [tbuffer_length];
    printf("enter the temperature value");
    scanf("%7c", tbuffer);
    char *t;
    t = fgets (tbuffer, tbuffer_length, stdin );
    if(tbuffer[0] = 'A')
    {

    }
    if (tbuffer[0] = 'B')
    {

    }
    if (tbuffer[0] = 'C')
    {

    }

return 0;
}

在这种情况下，用户输入字符串值(例如:char buffer[7]= {'A', '+', '2', '5', '.','5','\r'} ) 如何将此字符串解释为 A 有设备 A 或 B 有设备 B，+25.5 有温度值(我想将此温度值转换为整数)和回车。解释并将其转换为整数后，我需要通过接口(interface)发送(我知道如何通过接口(interface)发送)。给我一些解释上的想法。

Answer 1

使用==运算符比较值

int main()
{
printf("Welcome to the temperature control program:\n");
    printf("enter the ascii temperature characters");
    printf("enter the ascii characters of an euipment name with + or - and followed by a integer value");
    printf("type character terminated by carriage return");

    char tbuffer [tbuffer_length];
    printf("enter the temperature value");
    scanf("%7c", tbuffer);
    char *t;
    t = fgets (tbuffer, tbuffer_length, stdin );
    if(tbuffer[0] == 'A')
    {

    }
    if (tbuffer[0] == 'B')
    {

    }
    if (tbuffer[0] == 'C')
    {

    }

return 0;
}