linux - BASH:变量仅显示最后一行

Question

该变量仅显示最后一行:

while read var1; do
    var2+="$var1"$"\n"
    if [[ $var2 == *andoi* ]]; then
        break
    fi
done < "./filename" #or other file
echo "Result:"
echo "$var2" #just read the last lines, I want all
#...edit $var2...etc...
echo "$var2" #modified

简化的脚本:

while read var1; do
    var2+="$var1"$"\n"
done < "./filename" #or other file
echo "$var2" #just read the last lines, I want all
#...edit $var2...cdn...
echo "$var2" #modified

我用过这个http://gsteph.blogspot.com/2007/04/bash-reading-text-file.html

dentry 变量如何显示一个变量中的所有行？

//我更正了，可能对某人有用。//

Answer 1

所以您想将 $var1 累加到 $var2 中？

while read var1; do
  var2="$var2 $var1"
  # etc...
done < "./filename"

echo "$var2"

要在每个上累积换行符，请执行以下操作:

while read var1; do
  var2="$var2
$var1"
  # etc...
done < "./filename"

echo "$var2"