python - Pandas 过滤(〜isin)不起作用

Question

这是我的数据

 omzet_activity_paid_count_january_devices

No    Text    
1     dcbjkd
2     hdgfhds
3     dsdfs
33    jhsda
40    ydgyua

我期待像这样过滤数据

omzet_activity_paid_count_january_devices

No    Text    
3     dsdfs
40    ydgyua

这是我做的

user_internal = ['1','2','33']
omzet_activity_paid_count_january_devices = omzet_activity_paid_count_january_devices[~omzet_activity_paid_count_january_devices.No.isin(user_internal)]

上面的代码不工作，输出仍然像我原来的数据帧，我错过了什么？

Answer 1

我认为你有混合类型的问题 - 数字和字符串。

omzet_activity_paid_count_january_devices.No.dtype
dtype('O')

omzet_activity_paid_count_january_devices.No.head().tolist()
[1, 2, 3, 33, 40] 

因此将 No 列转换为字符串:

user_internal = ['1','2','33']
mask = ~omzet_activity_paid_count_january_devices.No.astype(str).isin(user_internal)
omzet_activity_paid_count_january_devices =  omzet_activity_paid_count_january_devices[mask]

或者将 string 从列表更改为 int:

user_internal = [1,2,33]
mask = ~omzet_activity_paid_count_january_devices.No.isin(user_internal)
omzet_activity_paid_count_january_devices =  omzet_activity_paid_count_january_devices[mask]