c - 系统调用 : Outputing file and pausing every 20 lines

Question

因此，我正在读取文件并使用系统调用将文件内容输出到控制台。我还想在输出中每遇到 20 行就添加一个空格。这是我遇到麻烦的地方，因为尽管有以下几行代码，但整个文件的显示都没有空格

     //Write file contenst
  while( (nReadFile = read(nOpenFile, buffer, 1) != 0))
{
  write(1, &nLineCount, sizeof(nLineCount));

  if(nLineCount == 20)
    {
      write(1, "\n", 2);
      nLineCount = 0;
    }

  if(nReadFile = write(1, buffer, nReadFile) == '\n')
    {
      nLineCount++;
    }

}

这是整个程序(不包括包含库的 .h 文件)

  #include"mymore.h"

int main(int argCount, char *argv[])
{

  struct termios initial_settings, new_settings;

  tcgetattr(fileno(stdin), &initial_settings);
  new_settings=initial_settings;
  new_settings.c_lflag &= ~ICANON;
  new_settings.c_lflag &= ~ECHO;
  new_settings.c_cc[VMIN] = 1;
  new_settings.c_cc[VTIME] = 0;
  if (tcsetattr(fileno(stdin), TCSANOW, &new_settings)!=0)
    {
      fprintf(stderr, "could not set attributes\n");
    }

  int nLineCount = 0;

  int nCheckFile = 0;
  int nFileCountCounter = 1; //first arguement interested in is argv[1]
  int nOpenFile = 0;
  int nReadFile = 0;
  int nCount = 0;
  char *cData;
  char buffer[0];

  //check that arguements have been provided
  if( argCount < 2)
    {
      write(1, "There needs to be at least one file provided! \n", 50);
      return 1;
    }

  do 
    {
  printf("%d", argCount);
  //check if file exists
  nCheckFile = access(argv[nFileCountCounter], F_OK);

  if(nCheckFile != 0) //if file does not exist
{
  write(1, "The file ", 10);
  write(1, argv[nFileCountCounter], strlen(argv[1]));
  write(1," does not exist! \n", 25);
  return 1;
}
  else //file does exist
{
  write(1, "Opening ", 10);
  write(1, argv[nFileCountCounter], strlen(argv[1]));
  write(1, "\n", 2);
}

  //open the file
  nOpenFile = open(argv[nFileCountCounter], O_RDONLY);

  if(nOpenFile < 0)
{
  write(1, "Failed to open file ", 10);
  write(1, argv[nFileCountCounter], strlen(argv[nFileCountCounter]));
  write(1, "\n", 2);
  return 1;
}

  //read file
  cData = (char *) malloc(100 * sizeof(char));



  cData[nReadFile] = '\0';//append null terminator

  //find length of source file
  while(cData[nCount] != 0)
{
  nCount++;
}

  //Write file contenst
  while( (nReadFile = read(nOpenFile, buffer, 1) != 0))
{
  write(1, &nLineCount, sizeof(nLineCount));

  if(nLineCount == 20)
    {
      write(1, "\n", 2);
      nLineCount = 0;
    }

  if(nReadFile = write(1, buffer, nReadFile) == '\n')
    {
      nLineCount++;
    }

}

  cout << nLineCount << endl;
  //close file
  close(nOpenFile);

  //Increment to next file
  nFileCountCounter++;

}while(nFileCountCounter < argCount);//while there are still arguements

  tcsetattr(fileno(stdin), TCSANOW, &initial_settings); 
  return 0;
}

这实际上是我第一次使用系统调用，我想我注意到的一件事是 write 命令在任何 c 代码之前执行？

有什么想法吗？谢谢

Answer 1

你的代码中有很多错误:

1. char buffer[0];应该是 char buffer[1];

   char buffer[0];定义一个 buffer可以存储零字符，我想这不是你想要的。

2. write(1, "There needs to be at least one file provided! \n", 50);应该是

   char *msg = "There needs to be at least one file provided! \n";
   write(1, msg, strlen(msg));
   

   消息超过50条，有几个类似的错误，可以类似修复。

3. while( (nReadFile = read(nOpenFile, buffer, 1) != 0))应该是

   while( (nReadFile = read(nOpenFile, buffer, 1)) != 0)
   

   在 C 中，运算符 !=优先级高于 = , 所以 nReadFile = read(nOpenFile, buffer, 1) != 0测量 nReadFile = (read(nOpenFile, buffer, 1) != 0) .

4. if(nReadFile = write(1, buffer, nReadFile) == '\n')

   如果你想检查当前字符是否是换行符，你应该像if (buffer[0] == '\n')这样的东西.

5. cout << nLineCount << endl;

   这是 C++，不是 C。