python - Instagram 私有(private) API 403，即使有 cookie 和 header

Question

需要您的建议来避免 403 私有(private) Isntagram API 的使用。

我在网络上重复使用了一个 istagram scraper 代码。我做了几次尝试，甚至连标题和 cookie 都看起来接下来。从 post url 中直接获取信息并提取它没有问题。虽然，发表评论跨越多个页面并切换到下一个我需要通过身份验证。这只是测试身份验证的第一步。

    from botocore.vendored import requests
    import urllib.parse
    import hashlib
    import json
    def lambda_handler(event, context):
        CHROME_UA = 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_12_6) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/65.0.3325.181 Safari/537.36'
        def getSession(rhx_gis, csrf_token, variables):
            """ Get session preconfigured with required headers & cookies. """
            #"rhx_gis:csfr_token:user_agent:variables"
            print(variables)
            values = "%s:%s:%s:%s" % (
                    rhx_gis,
                    csrf_token,
                    CHROME_UA,
                    variables)
            x_instagram_gis = hashlib.md5(values.encode()).hexdigest()
        
            session = requests.Session()
            session.headers = {
                    'user-agent': CHROME_UA,
                    'x-instagram-gis': x_instagram_gis
                    }
            print(x_instagram_gis)
            session.cookies.set('ig_pr', '2')
            session.cookies.set('csrftoken', csrf_token)
        
            return session
        
        def runX():
            session = requests.Session()
            session.headers = { 'user-agent': CHROME_UA }
            response = session.get("https://www.instagram.com/selenagomez")
            data = json.loads(response.text.split("window._sharedData = ")[1].split(";</script>")[0])
            csrf = data['config']['csrf_token']
            rhx_gis = data['rhx_gis']
            variables = '{"id":"460563723","first":10,"after":"AQBf8puhlt8nU2JzmYdMMTuH0FbMgUM1fnIOZIH7n94DM4VLWkVILUAKVB-5dqvxQEI-Wd0ttlEDzimaaqwC98jccQaDQT4tSF56c_NlWi_shg"}'
            session = getSession(rhx_gis, csrf, variables)
        
            query_hash = '33ba35852cb50da46f5b5e889df7d159'
            encoded_vars = urllib.parse.quote(variables, safe='"')
            url = 'https://www.instagram.com/graphql/query/?query_hash=%s&variables=%s' % (query_hash, encoded_vars)
            print(url)
            opp = session.get(url)
            print(opp.status_code)
        runX();

4 月 16 日更新 -> 已修复

1. 问题已解决，现已收到 200 个。将哈希更改为 query_hash = 'ac38b90f0f3981c42092016a37c59bf7'并从 x-instagram-gis 计算中删除用户代理:

   值 = "%s:%s:%s"% (rhx_gis,csrf_token,变量)

Answer 1

自 2018 年 4 月 23 日起，您似乎不再需要 cookie 管理或 csrf token 。以下应该是您所需要的:

def getSession(rhx_gis, variables):
        values = "%s:%s" % (
                rhx_gis,
                variables)
        x_instagram_gis = hashlib.md5(values.encode()).hexdigest()

        session = requests.Session()
        session.headers = {
                'x-instagram-gis': x_instagram_gis
                }

        return session