Linux shell : my `expect` script doesn't work as expected

Question

我有一个如下所示的简单脚本，从命令行读取 2 个数字并将它们加在一起:

$cat runexp.sh
#!/bin/bash
echo "read 1st number"
read n1
echo "read 2nd number"
read n2
expr $n1 + $n2

可以运行，没问题。然后我编写了一个预期脚本，如下所示:

$cat autorun.sh
#!/usr/bin/expect
spawn ./runexp.sh
expect 'read 1st number' {send "1"}
expect 'read 2nd number' {send "2"}
interact

好像还是提示从命令行读取，等了好久才结束。

$./autorun.sh
spawn ./runexp.sh
read 1st number
5
4
3
5
4
3
read 2nd number
9

我哪里出错了？谢谢。

Answer 1

您还必须发送换行符，否则它只会等待(至少直到默认超时，我认为是十秒)。

此外，expect 不喜欢用单引号来括住字符串。与 Tcl(它的来源)一样，它需要双引号或大括号。这工作得很好:

#!/usr/bin/expect

spawn ./runexp.sh

expect "read 1st number" {send "1\n"}
expect {read 2nd number} {send "2\n"}

interact