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python - 每 X 秒作为用户输入运行 python 脚本

转载 作者:太空宇宙 更新时间:2023-11-04 04:38:51 25 4
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我有以下 python 代码:

#!/usr/bin/python
# -*- coding: utf-8 -*-
import json
import requests
import sys
import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText

#Function to get the health of the cluster
def getClusterHealth():
try:
response = requests.get('http://127.0.0.1:2379/health')
data = response.json()
if data['health']=="true":
print("Cluster is healthy")
getClusterMetrics()
elif data['health']!="true":
print ("Cluster is not healthy")
sendEmail()
except requests.exceptions.ConnectionError as e:
print e
print("Cluster is down")
sendEmail()

#Function to get the netrics of the cluster
def getClusterMetrics():
try:
response = requests.get('http://127.0.0.1:2379/metrics')
with open('clusterMetrics.txt','w') as f:
f.write(response.text)
f.close()
print("Cluster Metrics saved in file: clusterMetrics.txt")
except requests.exceptions.ConnectionError as e:
print e
sendEmail()

#Function to send emails in case of failures
def sendEmail():
msg = MIMEText("etcd Cluster Down Sample Mail")
sender = "etcd Cluster - 10.35.14.141"
recipients = ["sample@email.com"]
msg["Subject"] = "etcd Cluster Monitoring Test Multiple ID"
msg['From'] = sender
msg['To'] = ", ".join(recipients)
s = smtplib.SMTP('localhost')
s.sendmail(sender,recipients,msg.as_string())
s.quit()

if __name__ == "__main__":

if(len(sys.argv) < 2):
print("Usage : python etcdMonitoring.py [health|metrics]")
elif(sys.argv[1] == "health"):
getClusterHealth()
elif(sys.argv[1] == "metrics"):
getClusterMetrics()

我想在用户输入时运行整个脚本 X 秒。但是,使用此输入,我想在我的函数中执行一些基于计时器的功能。它应该按照我的意愿显示输出/做某些事情(不能在这里显示代码),但是内部函数将针对用户给定的输入倍数运行。例如,如果输入为 30,则脚本应每 30 秒运行一次,但我应该能够每两分钟检查一次集群是否健康。

最佳答案

我前段时间遇到过这样的问题,把你想每X秒执行一次的代码放在一个函数中然后使用threading python模块将它作为一个线程运行,但是不要忘记关闭线程在关闭程序之前使用 thread.cancel()thread.exit()(使用 atexit 或您自己的实现),因为函数将继续如果你不这样做,就执行。

import atexit
import threading
X = input("Repeat code every ? sec")
def code(X):
thread = threading.Timer(float(X), code)
thread.start()
'''
your
code
'''
def exit():
thread.cancel() #or thread.exit()
atexit.register(exit)

更多信息:
Run certain code every n seconds
How to close a thread from within?

关于python - 每 X 秒作为用户输入运行 python 脚本,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/51102631/

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