c - 如何用 millis() 替换 delay()？

Question

过了一会儿，我得到了我想要的最终结果，但我不能使用延迟，因为我需要不同的时间来处理不同的 strip ，所以我需要用 millis 替换 delay() () 在这段代码中:

#include <FastLED.h>
#define NUM_LEDS1 10
#define NUM_LEDS2 6
#define DATA_PIN1 6
#define DATA_PIN2 7
CRGB leds1[NUM_LEDS1];
CRGB leds2[NUM_LEDS2];

void setup() { 
  FastLED.addLeds<NEOPIXEL, DATA_PIN1>(leds1, NUM_LEDS1);
  FastLED.addLeds<NEOPIXEL, DATA_PIN2>(leds2, NUM_LEDS2);
}

int dot_delay1[ ] = { 100,200,300,400,500,600,700,800,900,1000 };
int dot_delay2[ ] = { 100,200,300,400,500,600 };

void loop() {
  for(int dot = 0; dot < NUM_LEDS1; dot++)
    for(int dot = 0; dot < NUM_LEDS2; dot++) 
    { 
      leds1[dot] = CRGB::Blue;
      leds2[dot] = CRGB::Blue;
      FastLED.show();
      leds1[dot] = CRGB::Black;
      leds2[dot] = CRGB::Black;
      delay( dot_delay1[ dot ] );
      // this is where I need to put the second delay,
      // but I can't put more then 1 delay.
      // I need to refactor my code with millis() function instead of delay()
    }
}

Answer 1

您可以使用以特殊频率或时间执行的非阻塞代码模式。在下文中，我将向您提供一个简短示例，说明如何在不阻塞主循环的情况下替换 delay(1000) 和 delay(5000)。此外，您可以检查 stackoverflow 是否有类似的帖子(例如 Pause without Delay() arduino )。

// 1 sec. frequency
unsigned long interval=1000;    // the time we need to wait
unsigned long previousMillis=0; // millis() returns an unsigned long.

// 5 sec. frequency  
unsigned long interval1=5000;    // the time we need to wait
unsigned long previousMillis1=0; // millis() returns an unsigned long.

void setup() {
   //...
}

void loop() {

 // other CMD's...

 // replace delay(1000) 
 if ((unsigned long)(millis() - previousMillis) >= interval) {
    previousMillis = millis();
    // every first second
    // ... 
 }

 // other CMD's...

 // replace delay(5000) 
 if ((unsigned long)(millis() - previousMillis1) >= interval1) {
    previousMillis1 = millis();
    // every fifth second
    // ... 
 }

 // other CMD's...
}