c - 休息;未选择正确选项时出现问题。

Question

我是新手，正在学习编程，但无法正确“中断”它。如果硬币不是 0、5、10 或 25，它应该“打破”(最后一个 if)。该程序应该像自动售货机一样工作，只使用 10 美分、5 分硬币、25 美分硬币，当有人进入时“0”停止数硬币。

#include <stdio.h>
#define NICKEL 5
#define DIME 10
#define QUARTER 25

int main(void)
{
int coins;
int sum  = 0;

    printf("Insert Coins: ");
    scanf("%d",&coins);

    while (coins != 0){
    sum += coins;
        if (coins == NICKEL){
            printf("Insert coins: ");
            scanf("%d",&coins);}
        else {continue;}

        if (coins == DIME){
            printf("Insert Coins: ");
            scanf("%d",&coins);}
        else {continue;}

        if (coins == QUARTER){
            printf("Insert Coins: ");
            scanf("%d",&coins);}
        else {continue;}

     if (coins != NICKEL || coins != DIME || coins != QUARTER || coins !=0){
            break;
            printf("wrong coin");}

        printf("the amount you put in: %d",sum);

    }

Answer 1

我认为你正在尝试这样做，

#include <stdio.h>
#define NICKEL 5
#define DIME 10
#define QUARTER 25

int main(void)
{
  int coins;
  int sum  = 0;

  do {
    printf("Insert Coins:");
    scanf("%d", &coins);
    if(coins == NICKEL || coins == DIME || coins == QUARTER) {
      sum += coins;
    } else if(coins == 0) {
      break;
    } else {
      printf("Wrong Coin\n");
    }
  }while(1); // Infinite Loop.

  printf("The amount you put in %d\n", sum);
}