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c - 在某些测试用例之后,堆被损坏

转载 作者:太空宇宙 更新时间:2023-11-04 04:22:33 25 4
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#include <cstdlib>
#include <stdio.h>
int *starting_time = NULL;
int *frequency_time = NULL;
int *duration_time = NULL;
int *toured_cities = NULL;


int check(int t,int i,int s, int a){
int k; int p=starting_time[i];
while (1){
k= p+frequency_time[i];
if (k>a) return p;
else if ((k-t)>=s) return k;
p=k;
}
}

void sight_seeing(){
int c,s,a; int size=4;
scanf("%d\n%d\n%d",&c,&s,&a);
starting_time=(int *)realloc(starting_time,size*sizeof(int));
frequency_time=(int *)realloc(frequency_time,size*sizeof(int));
duration_time=(int *)realloc(duration_time,size*sizeof(int));
toured_cities = (int *)realloc(toured_cities,size*sizeof (int));

for (int i=1;i<c;i++){
scanf("%d",&starting_time[i]);
scanf("%d",&frequency_time[i]);
scanf("%d",&duration_time[i]);
toured_cities[i]=0;
}
int t = 0;int x = 0;int i=1;int k;bool q;
while (t<a){
if (i==c) break;
if ((starting_time[i]-t)>=s) {
k=starting_time[i];
x++;
}
else{
k = check(t,i,s,a);
if ((k+duration_time[i])<a) x++;
else if ((k+duration_time[i])==a)
{
if (i<c-1) k=starting_time[i];
}
}
t=k+duration_time[i];
if (t>a) toured_cities[i]=0;
else toured_cities[i]=1;
i++;
}
for (int i=1;i<c;i++){
if (toured_cities[i]==1) q=1;
else q=0;
}
if (q==1 && x>=0) printf("The maximum sightseeing possible %d \n",x);
else printf("\nSightseeing is not Impossible\n");
starting_time = (int *)realloc(starting_time,0);
frequency_time = (int *)realloc(frequency_time, 0);
duration_time = (int *)realloc(duration_time,0);
toured_cities = (int *)realloc(toured_cities,0);
}


int main(int argc, char** argv) {
int n;
scanf("%d",&n);
while (n--){
sight_seeing();
}
return 0;
}

这是我的代码。此代码通过小于 10 的测试用例。但是对于测试用例 100。我收到此错误。

          *** Error in `./prog': free(): invalid next size (fast): 
0x00002b2db77fac20 ***
======= Backtrace: =========
/lib/x86_64-linux-gnu/libc.so.6(+0x70bcb)[0x2b2db738dbcb]
/lib/x86_64-linux-gnu/libc.so.6(+0x76f96)[0x2b2db7393f96]
/lib/x86_64-linux-gnu/libc.so.6(+0x7778e)[0x2b2db739478e]
./prog(+0xcd3)[0x2b2db643acd3]
./prog(+0x875)[0x2b2db643a875]
/lib/x86_64-linux-gnu/libc.so.6(__libc_start_main+0xf1)
[0x2b2db733d2b1]
./prog(+0x93a)[0x2b2db643a93a]
======= Memory map: ========
2b2db643a000-2b2db643b000 r-xp 00000000 fd:00 17031175
/home/S5BAtg/prog
2b2db643b000-2b2db643f000 rw-p 00000000 00:00 0
2b2db6448000-2b2db644d000 rw-p 00000000 00:00 0
2b2db663b000-2b2db663c000 r--p 00001000 fd:00 17031175
/home/S5BAtg/prog
2b2db663c000-2b2db663d000 rw-p 00002000 fd:00 17031175
/home/S5BAtg/prog

这是错误,我收到了。另外,请帮我分析一下代码的复杂性。

最佳答案

主要问题是:

  • 您仅为 5 个条目重新分配数组。一旦您读取了 6 的值对于 c ,您可以访问和修改超出这些数组末尾的条目。

还有很多问题:

  • 您不能从 C 中的运行时表达式初始化全局对象:int *starting_time = (int *)malloc(sizeof(int));是无效的。实际上,您必须将此代码编译为 C++ 并提供头文件 <cstdlib> .请注意,如果您只是将这些数组指针初始化为 NULL,您的代码将工作相同或者让它们保持未初始化和全局状态。

  • 具有短名称的全局变量,如 int c,s,a;被认为是糟糕的风格并且容易出错。您应该将所有这些变量设为本地变量 sight_seeing()功能。

  • 数组在 C 中是基于零的,循环 for (int i=1;i<c;i++)只迭代 c-1次,这可能不是故意的。

  • 用于验证是否可以完成完整游览的循环中存在逻辑错误:q是为每个城市设置的,因此它的值只反射(reflect)了最后一个城市是否可以访问。

这是一个改进的版本:

#include <stdio.h>
#include <stdlib.h>

int check(int t, int i, int a, int s, int *starting_time, int *frequency_time) {
int k;
int p = starting_time[i];
while (1) {
k = p + frequency_time[i];
if (k > a)
return p;
else
if (k - t >= s)
return k;
p = k;
}
}

void sight_seeing(void) {
int c, s, a;

if (scanf("%d\n%d\n%d", &c, &s, &a) != 3) {
printf("invalid input\n");
exit(1);
}
int *starting_time = (int*)calloc(c, sizeof(int));
int *frequency_time = (int*)calloc(c, sizeof(int));
int *duration_time = (int*)calloc(c, sizeof(int));
int *toured_cities = (int*)calloc(c, sizeof(int));

if (!starting_time || !frequency_time || !duration_time || !toured_cities) {
printf("cannot allocate memory\n");
exit(1);
}
for (int i = 0; i < c; i++) {
if (scanf("%d%d%d", &starting_time[i], &frequency_time[i], &duration_time[i]) != 3) {
printf("invalid input\n");
exit(1);
}
}
int t = 0;
int x = 0;
int i, k;
bool q;

for (i = 0; i < c && t < a; i++) {
if (starting_time[i] - t >= s) {
k = starting_time[i];
x++;
} else {
k = check(t, i, a, s, starting_time, frequency_time);
if (k + duration_time[i] < a)
x++;
else
if (k + duration_time[i] == a) {
if (i < c - 1)
k = starting_time[i];
}
}
t = k + duration_time[i];
if (t > a)
toured_cities[i] = 0;
else
toured_cities[i] = 1;
}
q = 1;
for (int i = 0; i < c; i++) {
if (toured_cities[i] == 0) {
q = 0;
break;
}
}
if (q == 1 && x >= 0)
printf("The maximum sightseeing possible %d \n", x);
else
printf("\nSightseeing is not Impossible\n"); // not sure what you mean?

free(starting_time);
free(frequency_time);
free(duration_time);
free(toured_cities);
}


int main(int argc, char **argv) {
int n;
if (scanf("%d", &n) == 1) {
while (n-- >0) {
sight_seeing();
}
}
return 0;
}

关于c - 在某些测试用例之后,堆被损坏,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/45127517/

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