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c - 为什么我的 Infix to postfix 程序给出了错误的输出(C,Stacks)

转载 作者:太空宇宙 更新时间:2023-11-04 04:21:22 25 4
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简介:我正在使用静态字符堆栈(使用结构和字符数组)在 C 编程语言中编写后缀程序的中缀。

我的方法论:我通常从工作代码开始,然后(当我知道算法有效时)使代码更清晰、更小。

完成:我只完成了我的程序的基本粗略代码,它给我错误的输出,所以我自己检查了几次并向我的 friend 展示了它,他也不能'不太明白。

问:如果有人可以看一下并告诉我为什么我得到错误的输出,如果可能的话,请指出我,这真的会帮助我,并可能使我成为更好的程序员正确的方向。

Insight: 我遇到的问题是,它不是在字母数字部分后添加 +、-、* 或/(就像 A+B 将是 AB+),而是给出随机字符他们的位置(像 AB| 或 AB├ 等)。这些字符在每次执行程序时都会发生变化。我相信它们是垃圾值,但不确定它们是如何被使用的。

enter image description here

代码:

#include <stdio.h>
#include <conio.h>
#include <ctype.h>

#define MAX 20

struct stackObj{

char stack[MAX];
int topOfStack;

};

void stackPush(struct stackObj *s, char value);
char stackPop(struct stackObj *s);
void stackPeekPrint(struct stackObj *s);
char stackPeek(struct stackObj *s);
int stackIsEmpty(struct stackObj *s);
int stackIsFull(struct stackObj *s);

int comparePrecedence(struct stackObj *s, char value);


int main(){

struct stackObj s;
s.topOfStack=0;

char result[MAX];
int resultFlag=0;

char exp[MAX];
gets(exp);

printf("\n\n");
printf("Expression:\t");
printf(exp);
printf("\n\n");


char _new='.';
char _old='.';
int i=0;
while (exp[i]!= '\0'){

_new = exp[i];
i++;

if (_new=='+' || _new=='-' || _new=='*' || _new=='/'){

if (comparePrecedence(&s,_new)==1){
stackPush(&s,_new);

} else if (comparePrecedence(&s,_new)==0){
_old = stackPop(&s);
result[resultFlag]=_old;
resultFlag++;
stackPush(&s,_new);
}

} else if (_new=='('){
stackPush(&s,_new);
}

else if (_new==')'){
_old = stackPop(&s);
while (_old != '('){
result[resultFlag]=_old;
resultFlag++;
_old = stackPop(&s);
}
stackPop(&s);

} else if (isalnum(_new) ) {
result[resultFlag]=_new;
resultFlag++;
}
}

while (s.topOfStack > 0) {
_old = stackPop(&s);
result[resultFlag]=_old;
resultFlag++;

}

printf("\n\n\n");
printf(result);
printf("\n\n\n");


return 0;
}

//----------------- Precedence Comparison CODE -----------------------------

int comparePrecedence(struct stackObj *s, char value){

//START - Variable Declarations and Definitions
int stackPrecedence = 0;
int operatorPrecedence = 0;

char stackChar = stackPeek(s);
char operChar = value;
//END - Variable Declarations and Definitions


//START - Setting Precedences
if (stackChar== '+'){ stackPrecedence=1; }
else if (stackChar== '-'){ stackPrecedence=1; }
else if (stackChar== '*'){ stackPrecedence=2; }
else if (stackChar== '/'){ stackPrecedence=2; }

if (operChar== '+'){ operatorPrecedence=1; }
else if (operChar== '-'){ operatorPrecedence=1; }
else if (operChar== '*'){ operatorPrecedence=2; }
else if (operChar== '/'){ operatorPrecedence=2; }
//END - Setting Precedences


//START - Comparing Precedences
if (operatorPrecedence > stackPrecedence) { return 1;
} else { return 0; }

}


//----------------- STACK CODE ------------------------------------------

void stackPush(struct stackObj *s, char value){

if ( (stackIsFull(s) != 1) && (s->topOfStack != MAX) ){

s->stack[s->topOfStack] = value;
s->topOfStack++;

} else {
printf("\nSorry, stack is full. No new data can be entered");
}


}

char stackPop(struct stackObj *s){

s->topOfStack = s->topOfStack-1;
return s->stack[s->topOfStack-1];


}

void stackPeekPrint(struct stackObj *s){

if (s->topOfStack != 0){
printf("\nTOS:\t%c", s->stack[(s->topOfStack)-1]);
} else {
printf("\nSorry stack is empty");
}

}

char stackPeek(struct stackObj *s){

if (s->topOfStack != 0){
return (s->stack[(s->topOfStack)-1]);
} else {
return '`';
}

}

int stackIsEmpty(struct stackObj *s){

if (s->topOfStack==0) {
return 1;
} else {
return 0;
}

}

int stackIsFull(struct stackObj *s){

if (s->topOfStack==MAX) {
return 1;
} else {
return 0;
}

}

最佳答案

在你正在做的stackPop()函数中

 s->topOfStack = s->topOfStack-1;
return s->stack[s->topOfStack-1];

应该是

 s->topOfStack = s->topOfStack-1;
return s->stack[s->topOfStack];

您实际上返回的是 s->stack[s->topOfStack-2]

关于c - 为什么我的 Infix to postfix 程序给出了错误的输出(C,Stacks),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/46531353/

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