c++ - 将进程的输出写入缓冲区

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How to execute a command and get output of command within C++?

在我的 C++ 程序中，我使用 execv/system 运行外部程序。

我想将程序的输出重定向到程序中的缓冲区，即:

char* buff[some size large enough for any possible output];
system(some program);
//THE PROGRAM I JUST RAN IS A SPECIAL BLACK BOX PROGRAM THAT RUNS
//AND PARSE AN HTTP DUMP FILE AND PRINTS IT TO THE SCREEN WHEN RUNNING
//I WANT THE OUTPUT TO GO A BUFFER IN MY PROGRAM.
//THE IDEA IS TO HAVE THE DATA OF THE OUTPUT ON THE BUFFER RATHER THAN ON A FILE

//have the buffer filled with the output of the program

谢谢:-)

Answer 1

我不确定是否还有其他方法可以做到这一点，但这就是我的想法

char* buff[some size large enough for any possible output];
system(some program >somefile.txt);  

//have the buffer filled with the output of the program
// And redirect it into a file


//Do initial validity checks and open the file



read(somefile.txt,buff,bufflen);
//Read the file

unlink somefile.txt 
//Unlink if the file is not needed

将 bufflen 替换为您要从文件中读取的字节数。