python - 如何在python中集成一个简单的菜单

Question

这是我当前的 HiLo 游戏，我想集成一个包含 4 个选项的菜单，1. 读取 csv 文件 2. 玩游戏 3. 显示结果和 4. 退出，任何帮助都将不胜感激。因为我不知道从哪里开始。

 import\
    random
n = random.randint(1,20)
print(n)
guesses = 0

while guesses < 5:
    print("Guess the number between 1 and 20")
    trial = input()
    trial = int(trial)

    guesses = guesses + 1

    if trial < n:
        print("higher")
    if trial > n:
        print("lower")
    if trial == n:
        print("you win")
        break

if trial == n:
    guesses = str(guesses)
    print("Congratulations it took" + " " + guesses + " " + "tries to guess my number")
if trial != n:
    n = str(n)
    print("Sorry, the number I was thinking of was" + " " + n + " ")`enter code here`

Answer 1

您可以将游戏循环放在菜单循环中，并将 csv 文件等的所有代码放在这些循环中...

但是，为了稍微组织一下代码，学习一点函数当然更可取:

在这里，我将您的游戏循环放在一个函数中，还为其他选项创建了函数；现在，它们只打印它们应该做的事情，但是当您添加功能时，您将用代码填充它。

import random


def read_csv():
    print('reading csv')

def show_results():
    print('showing results')

def play_game():
    n = random.randint(1,20)
#    print(n)
    guesses = 0 
    while guesses < 5:
        print("Guess the number between 1 and 20")
        trial = input()
        trial = int(trial)

        guesses = guesses + 1

        if trial < n:
            print("higher")
        if trial > n:
            print("lower")
        if trial == n:
            print("you win")
            break

    if trial == n:
        guesses = str(guesses)
        print("Congratulations it took" + " " + guesses + " " + "tries to guess my number")
    if trial != n:
        n = str(n)
        print("Sorry, the number I was thinking of was" + " " + n + " ")    


while True:

    choice = int(input("1. read csv file 2. play game 3. show results and 4. exit"))
    if choice == 4:
        break
    elif choice == 2:
        play_game()
    elif choice == 3:
        show_results()
    elif choice == 1:
        read_csv()