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python - 在同一轴上创建两个标签并填补周末空白

转载 作者:太空宇宙 更新时间:2023-11-04 04:17:00 25 4
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从这个问题中得到一些指导,在底部创建了我的条形图; Matplotlib - Finance volume overlay

但我似乎无法解决的问题是条形图的空白区域。正如你在代码中看到的,列表y3length=21,对于xy1<也是一样的y2。空的日子是周末,但这些日子在我创建任何图之前从列表 x 中删除。我看不出它们如何以及为什么会留下空隙,即使在我将它们从我的 x-axis 列表中删除后也是如此。

编辑:我缩短了问题。

]

from datetime import datetime,timedelta
import matplotlib
import matplotlib.pyplot as plt
import matplotlib.dates as mdates

d = datetime.strptime('2019-02-01','%Y-%m-%d')
#create x-axis which consists of all days in february except weekdays, plus the first day in march
x = []
for i in range(0,29):
if((d + timedelta(days=i)).date().weekday() > 4):
continue
x.append((d + timedelta(days=i)).date())

y1 = [317.92, 319.1, 322.73, 324.22, 322.05, 321.06, 323.79, 325.29, 325.55, 327.9, 329.99, 330.92, 331.33, 332.75, 331.41, 333.22, 332.58, 333.64, 331.19, 329.83, 332.46]
y2 = [-0.377507469, -0.3411700881, 0.055641283900000005, 0.44570105590000003, 0.10930618490000005, -0.2948038151, 0.09190098490000004, 0.12858223490000004, 0.09559385990000004, 0.4806987649, 0.11333709890000004, 0.5247366639000001, 0.11605396190000006, -0.30122159309999996, -0.7405398680999999, -0.7053236033999999, -0.33368165239999986, -0.8210733183999999, -1.2753887724, -1.3106836659999999, -1.3450585547999998]
y3 = [27, 15, 12, 4, 5, 11, 4, 14, 18, 19, 13, 17, 28, 22, 4, 15, 26, 21, 21, 21, 9]

fig, ax1 = plt.subplots()
ax1.plot(x, y1, 'b')
ax1.tick_params('y', colors='b')
#create space at the bottom for the bar-plot
pad = 0.25
yl = ax1.get_ylim()
ax1.set_ylim(yl[0]-(yl[1]-yl[0])*pad,yl[1])

fig.suptitle('Some title', fontsize=16)
ax2 = ax1.twinx()

ax2.plot(x, y2,'r')
ax2.tick_params('y', colors='r')
#create space at the bottom for the bar-plot
pad = 0.25
yl = ax2.get_ylim()
ax2.set_ylim(yl[0]-(yl[1]-yl[0])*pad,yl[1])
#create barplot and make it small by adding a (in this case, this is not a modular solution) max-limit
ax3 = ax1.twinx()
ax3.set_ylim(0,250)
ax3.bar(x, y3, color='green', width=1, alpha=0.5)
ax3.set_xlim(min(x),max(x))
ax3.get_yaxis().set_ticks([])

ax1.set_ylabel('1st Value', color='b')
ax2.set_ylabel('2nd Value', color='r')
plt.gcf().autofmt_xdate()
plt.gca().xaxis.set_major_formatter(mdates.DateFormatter('%d-%B'))

plt.show()

最佳答案

您的 x 轴没有周末数据

在下面的代码中,您创建了 x,但不包括周末。

x = []
for i in range(0,29):
if((d + timedelta(days=i)).date().weekday() > 4):
continue
x.append((d + timedelta(days=i)).date())

例如,如果 2 月 1 日是星期五,那么 x 数组的第一个元素是 [0, 3, 4, 5]。您不包括周末的数据,但通过省略 [1, 2] 您将离开他们占用的空间。

解决方案:删除周末的地点并处理标签格式

您应该做的是创建没有间隙的代理 x 轴数据,然后重新处理标签。一个完整的解决方案可能如下所示。

from datetime import datetime,timedelta
import matplotlib
import matplotlib.pyplot as plt
import matplotlib.dates as mdates
import matplotlib.ticker as ticker

d = datetime.strptime('2019-02-01','%Y-%m-%d')
#create x-axis which consists of all days in february except weekdays, plus the first day in march
x = []
dates = {}
day = 0
for i in range(0,29):
if((d + timedelta(days=i)).date().weekday() > 4):
continue
x.append(day)
dates[day] = (d + timedelta(days=i)).date()
day += 1


def format_date(x, pos=None):
return dates[int(x)].strftime('%d-%B')

y1 = [317.92, 319.1, 322.73, 324.22, 322.05, 321.06, 323.79, 325.29, 325.55, 327.9, 329.99, 330.92, 331.33, 332.75, 331.41, 333.22, 332.58, 333.64, 331.19, 329.83, 332.46]
y2 = [-0.377507469, -0.3411700881, 0.055641283900000005, 0.44570105590000003, 0.10930618490000005, -0.2948038151, 0.09190098490000004, 0.12858223490000004, 0.09559385990000004, 0.4806987649, 0.11333709890000004, 0.5247366639000001, 0.11605396190000006, -0.30122159309999996, -0.7405398680999999, -0.7053236033999999, -0.33368165239999986, -0.8210733183999999, -1.2753887724, -1.3106836659999999, -1.3450585547999998]
y3 = [27, 15, 12, 4, 5, 11, 4, 14, 18, 19, 13, 17, 28, 22, 4, 15, 26, 21, 21, 21, 9]

fig, ax1 = plt.subplots()
ax1.plot(x, y1, 'b')
ax1.tick_params('y', colors='b')
#create space at the bottom for the bar-plot
pad = 0.25
yl = ax1.get_ylim()
ax1.set_ylim(yl[0]-(yl[1]-yl[0])*pad,yl[1])

fig.suptitle('Some title', fontsize=16)
ax2 = ax1.twinx()

ax2.plot(x, y2,'r')
ax2.tick_params('y', colors='r')
#create space at the bottom for the bar-plot
pad = 0.25
yl = ax2.get_ylim()
ax2.set_ylim(yl[0]-(yl[1]-yl[0])*pad,yl[1])
#create barplot and make it small by adding a (in this case, this is not a modular solution) max-limit
ax3 = ax1.twinx()
ax3.set_ylim(0,250)
ax3.bar(x, y3, color='green', width=1, alpha=0.5)
ax3.set_xlim(min(x),max(x))
ax3.get_yaxis().set_ticks([])

ax1.set_ylabel('1st Value', color='b')
ax2.set_ylabel('2nd Value', color='r')
plt.gcf().autofmt_xdate()
plt.gca().xaxis.set_major_formatter(ticker.FuncFormatter(format_date))

plt.show()

这会产生图像

Look, no x gaps

这是相同的数据,但没有周末间隔。

差异说明

我在这个练习中改变了三个方面。首先,我将 x 设置为最终表示数组 [0, 1, 2, ..., 20],并创建了一个字典 dates跟踪 x[i] 代表哪一天。

x = []
dates = {}
day = 0
for i in range(0,29):
if((d + timedelta(days=i)).date().weekday() > 4):
continue
x.append(day)
dates[day] = (d + timedelta(days=i)).date()
day += 1

然后我创建了一个函数 format_date 以提供给 matplotlib.ticker 来处理 x 轴的标签。

def format_date(x, pos=None):
return dates[int(x)].strftime('%d-%B')

最后,我将 x 轴设置为使用此格式功能。这使用必须导入的 matplotlib.ticker

# in the imports, add
import matplotlib.ticker as ticker

# when describing the x-axis, use
plt.gca().xaxis.set_major_formatter(ticker.FuncFormatter(format_date))

关于python - 在同一轴上创建两个标签并填补周末空白,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55220323/

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