Python - 如果包含列表中元组的元素，则仅打印行

Question

我有以下文本文件:

We are playing football at World Cup
teste
We are playing football
Playing test 
World Cup Football

我只想提取包含 (World Cup and Football) 或 ('Playing', 'test') 的行。

例如，基于我的文本文件，我只想提取这个:

We are playing football at World Cup
Playing test 
World Cup Footbal

基本上我只想提取该行是否包含每个元组中的两个值。

为此，我正在尝试以下代码:

file = 'text.txt'
words = [('Football','World Cup'), ('Playing test ')]
with open(file, "r") as ins:
    for line in ins:
        if all(x in line.lower() for x in words):
            print(line)

但是我的代码出现了以下错误:

TypeError: 'in <string>' requires string as left operand, not tuple

我该怎么做？

谢谢

Answer 1

您可以尝试组合any 和all:

if any(all(words.lower() in line.lower() for words in word_tuples) for word_tuples in words)

您可以检查单词列表中的任何单词和列表中的所有项目。

(无文件测试)

# Note: second element needs to be tuple else causes unexpected results
words = [('Football','World Cup'), ('Playing test',)] 
ins = ["We are playing football at World Cup",
       "teste",
       "We are playing football",
       "Playing test",
       "World Cup Football"]

for line in ins:
    if any(all(words.lower() in line.lower() for words in word_tuples) for word_tuples in words):
        print(line)

输出:

We are playing football at World Cup
Playing test
World Cup Football

如以下评论所述，如果第二个元素不是元组，则会导致意外结果。使用测试示例，以下显示错误，因为它正在比较所有字符而不是单词是否相同:

x = "test palying"
if all(w.lower() in x for w in words[1]):
    print("ERROR")