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c - printf 和 long double

转载 作者:太空宇宙 更新时间:2023-11-04 04:14:28 24 4
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我在 Windows 上将最新的 gcc 与 Netbeans 一起使用。为什么 long double 不起作用? printf 说明符 %lf 是否错误?

代码:

#include <stdio.h>

int main(void)
{
float aboat = 32000.0;
double abet = 5.32e-5;
long double dip = 5.32e-5;

printf("%f can be written %e\n", aboat, aboat);
printf("%f can be written %e\n", abet, abet);
printf("%lf can be written %le\n", dip, dip);

return 0;
}

输出:

32000.000000 can be written 3.200000e+004
0.000053 can be written 5.320000e-005
-1950228512509697500000000000000000000000000000000000000000000000000000000000000
000000000000000000000000000000000000000000000000000000000000000000000000.000000
can be written 2.725000e+002
Press [Enter] to close the terminal ...

最佳答案

是的——对于long double,您需要使用%Lf(即大写的“L”)。

关于c - printf 和 long double,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/53489346/

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