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c - realloc - 将 int 转换为 char

转载 作者:太空宇宙 更新时间:2023-11-04 04:08:23 25 4
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我通过遍历整个数组将整数数组转换为 char,然后将生成的字符串添加到 ncurses 的方法 new_item。出于某种原因,我在 reallocate 内存的方式上做错了,因此我得到第一列:

-4 Choice 1                 0 Choice 1
4 Choice 2 1 Choice 1
4 Choice 3 - Instead of - 2 Choice 1
4 Choice 4 3 Choice 1
4 Exit 4 Choice 1

-

#include <stdio.h>
#include <stdlib.h>
#include <curses.h>
#include <menu.h>

#define ARRAY_SIZE(a) (sizeof(a) / sizeof(a[0]))
#define CTRLD 4

char *choices[] = {
"Choice 1",
"Choice 2",
"Choice 3",
"Choice 4",
"Exit",
};
int table[5]={0,1,2,3,4};
int main()
{ ITEM **my_items;
int c;
MENU *my_menu;
int n_choices, i;
ITEM *cur_item;

initscr();
cbreak();
noecho();
keypad(stdscr, TRUE);

n_choices = ARRAY_SIZE(choices);
my_items = (ITEM **)calloc(n_choices + 1, sizeof(ITEM *));

char *convert = NULL;
for(i = 0; i < n_choices; ++i){
convert = (char *) malloc ( sizeof(char) * 4);
sprintf(convert, "%i", table[i]);
my_items[i] = new_item(convert, choices[i]);
}
my_items[n_choices] = (ITEM *)NULL;

my_menu = new_menu((ITEM **)my_items);
mvprintw(LINES - 2, 0, "F1 to Exit");
post_menu(my_menu);
refresh();

while((c = getch()) != KEY_F(1))
{ switch(c)
{ case KEY_DOWN:
menu_driver(my_menu, REQ_DOWN_ITEM);
break;
case KEY_UP:
menu_driver(my_menu, REQ_UP_ITEM);
break;
}
}

char *n = NULL, *d = NULL;

unpost_menu(my_menu);
free_menu(my_menu);
for(i = 0; i < n_choices; ++i){
n = (char *) item_name (my_items[i]);
free (n);
d = (char *) item_description (my_items[i]);
free (d);
free_item(my_items[i]);
}

free(my_items);
endwin();
}

**更新:这已被修复。见上面的代码!

最佳答案

您尝试 realloc一次又一次地使用相同大小的相同内存块,realloc 只是返回相同的内存块。因此,您将覆盖 convert 的早期值,并在所有项目中存储相同的 char 数组。

您应该改用 malloc:

// right here
char *convert = NULL;
for(i = 0; i < n_choices; ++i){
convert = (char *) malloc (sizeof(char) * 4);
sprintf(convert, "%i", table[i]);
my_items[i] = new_item(convert, choices[i]);
}

关于c - realloc - 将 int 转换为 char,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/2936949/

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