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python - 如何读取plist中的响应字符串?

转载 作者:太空宇宙 更新时间:2023-11-04 04:06:18 24 4
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我正在尝试解析 plist 以获取字段“此提交中修复了哪些更改错误?”的响应字符串如下但不知何故它总是空的?有人可以就错误原因提供指导吗?

plist 片段:

<dict>
<key>description</key>
<string>What Change bugs are fixed in this submission? </string>
<key>id</key>
<string>7</string>
<key>multiline</key>
<string>1</string>
<key>releases</key>
<array>
<string>Yukon</string>
</array>
<key>response</key>
<string>&lt;change://problem/45317899&gt; hostapd to include IOKit framework
&lt;change://problem/35143400&gt; Yukon: hostapd-33 contains references to deprecated TARGET_OS_EMBEDDED macro</string>
</dict>

代码:-

from lxml import etree as et
plistfile = '/Users/username/autosubmissionlogs/Yukon/02192019_200740/hostapd-34/hostapd-34.plist'
with open(plistfile) as raw:
# Parse the XML input file into a tree.
tree = et.parse(raw)
stringUsedAsKey = tree.xpath("/plist/dict/dict/string"
+ "[./text()=\"What Change bugs are fixed in this submission?\"]")[0]
interestingDict1 = stringUsedAsKey.getparent()
string = interestingDict1.xpath("key[text()=\"response\"]/following-sibling::string")[0]
print('Changes \n:'%string)

预期输出:-

&lt;change://problem/45317899&gt; hostapd to include IOKit framework
&lt;change://problem/35143400&gt; Yukon: hostapd-33 contains references to deprecated TARGET_OS_EMBEDDED macro

最佳答案

问题是您打印结果的方式。这是正确的方法。

from lxml import etree as et
plistfile = '/Users/username/autosubmissionlogs/Yukon/02192019_200740/hostapd-34/hostapd-34.plist'
with open(plistfile) as raw:
# Parse the XML input file into a tree.
tree = et.parse(raw)
stringUsedAsKey = tree.xpath("/plist/dict/dict/string"
+ "[./text()=\"What Change bugs are fixed in this submission?\"]")[0]
interestingDict1 = stringUsedAsKey.getparent()
string = interestingDict1.xpath("key[text()=\"response\"]/following-sibling::string")[0]
print("{}{}".format('Changes \n:', string.xpath("text()")))

关于python - 如何读取plist中的响应字符串?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/57318382/

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