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python - 如何使用 guizero 知道谁是 python 井字游戏的赢家

转载 作者:太空宇宙 更新时间:2023-11-04 04:03:47 27 4
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我创建了一个名为 Tic Tac Toe 的游戏。有 2 位玩家,其中一位是 Xs,其中一位是 Os,您所要做的就是在没有其他人阻挡您的情况下连续获得您的符号 3。

游戏的 Gui 看起来像这样:

enter image description here

代码:

from guizero import App, TextBox, PushButton, Text, info

empty = ' '
player = "X"
def clicked(z):
button = buttonlist[int(z)] # Finds out which button was pressed
global empty, player
if button.text != empty:
pass # If button already pushed do nothing
else:
# Marks button with user's go
button.text = player
# Switches players
if player == "X":
player = "O"
else:
player = "X"
return

def instructions():
info("Instructions","There are 2 players one of them are Xs one of them are Os. All you have to do is you have to try getting your symbol 3 times in a row without the other player blocking you")
def quit_game():
app.destroy()

app = App(title="Tic Tac Toe", layout="grid", width=200, height=250)
buttonlist = [] # Empty list to contain a list of Buttons

Player1_label = Text(app, text="Player 1", align="top", grid=[0, 0, 2 , 1])
Player1 = TextBox(app, text=empty, align="top", grid=[2, 0, 3, 1])# Player 1 enters the username

Player2_label = Text(app, text="Player 2", align="top", grid=[0, 1, 2 , 1])
Player2 = TextBox(app, text=empty, align="top", grid=[2, 1, 3, 1])# Player 2 enters the username

Instructions = PushButton(app, command=instructions, text="Instructions", grid=[0, 5, 3, 1])# Display the instructions

Quit = PushButton(app, command=quit_game ,text="Quit",grid=[10, 0, 3, 2])

# Create Buttons for game, in 3 rows of 3
z=0
for x in range(3):
for y in range(2, 5):
buttonlist.append(PushButton(app, text=empty, args=str(z), grid=[x, y], command=clicked))
z+=1

app.display()

我的问题是显示谁是赢家。我知道如何让一个窗口出现以显示获胜者,执行此操作的行是:

app.info("Tic Tac Toe Winner","获胜者是"+ Player1.value)

但我遇到的问题是在比赛结束时知道谁是赢家,并显示他们是赢家我也觉得找出赢家与 有关buttonlist 我制作的列表,但我不知道该怎么做,所以如果有人能帮助我,我会很感激。

谢谢

最佳答案

不错的游戏。要使用游戏板,我建议创建一个内部数据表示,而不是根据惯例一直使用 gui 元素。

原因是,如果你在任何地方都使用 gui 元素,它可能会更慢,因为它不是理想的数据表示。您无法使用 pickle 等保存数据,并且还对您使用的 gui 框架添加了强烈的依赖性​​。例如。如果您以后打算将其转换为 Web 应用程序等,您将很难过。

所以我只是创建了一个简单的数据表示,我将字段存储在二维数组中。

# check_win checks if there are three markings
# in one row/column or diagonally
def check_win():
# the checks array is just a trick to
# reduce the amount of code,
# you could avoid it by just adding
# one nested loop where the outer iterates
# over y and the inner over x
# one with the outer on x and the inner on y
# and then two others with just one loop
# for the diagonals
# the body of the inner loops would
# esentially look the same as for the while
# loop below
checks= [(0, 0, 1, 1), (0, 2, 1, -1)]
for i in range(3):
checks.append((i, 0, 0, 1))
checks.append((0, i, 1, 0))
won= None
for y, x, incr_y, incr_x in checks:
player= field[y][x]
found= player is not None
while found and x < 3 and y < 3:
found= (player == field[y][x])
y+= incr_y
x+= incr_x
if found:
won= player
break
return won

# I also changed your clicked method a bit, so
# it calles the check_win method
# and also changed the signature, so
# it gets the y and x coordinate of the
# button which makes maintaining the
# field array inside the clicked method
# a bit simpler and also seems more natural
# to me
def clicked(y, x):
button = buttonlist[y][x] # Finds out which button was pressed
global empty, player
if button.text != empty:
pass # If button already pushed do nothing
else:
# Marks button with user's go
button.text = player
field[y][x] = player
# Switches players
if player == "X":
player = "O"
else:
player = "X"
won= check_win()
if won is not None:
print(f'Player {won} has won the game')
return

# now I initialize the field array
# it will contain None for an untouched
# cell and X/O if taken by the corresponding
# user
field= [[None] * 3 for i in range(3)]
buttonlist= list()

# to get the buttons to call the
# clicked function with the new
# signature and also maintain the
# buttons in a two dimensional array
# I changed the order of your loops
# and the args argument
for y in range(0, 3):
rowlist= list()
buttonlist.append(rowlist)
for x in range(3):
rowlist.append(PushButton(app, text=empty, args=(y, x), grid=[x, y+2], command=clicked))
z+=1

app.display()


# a plain vanilla version of check_win would look something like:

def check_win():
for start in range(3):
x= start
mark= field[0][x]
for y in range(1, 3):
if field[y][x] != mark:
# the sequence is not complete
mark= None
if mark is not None:
# player who set the mark won
return mark
y= start
mark= field[y][0]
for x in range(1, 3):
if field[y][x] != mark:
# the sequence is not complete
mark= None
if mark is not None:
# player who set the mark won
return mark
mark= field[0][0]
for x in range(1, 3):
if field[y][x] != mark:
# the sequence is not complete
mark= None
if mark is not None:
# player who set the mark won
return mark
mark= field[0][3]
for x in range(1, 3):
if field[y][2-x] != mark:
# the sequence is not complete
mark= None
if mark is not None:
# player who set the mark won
return mark
return None

关于python - 如何使用 guizero 知道谁是 python 井字游戏的赢家,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/57744832/

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