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linux - 系统命令返回是什么?

转载 作者:太空宇宙 更新时间:2023-11-04 04:02:25 25 4
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我有一个这样的模块。首先,我想解释所有 logger($arg1,$arg2) 将输出放在控制台上,它是为此创建的。并且参数 $source_server,@source_user,@log_name_pattern,@log_name_pattern,@archive_interval,@move_interval 是从 .csv 文件读取的,它们没有问题。

use constant OUTPUT_PATH => "./outputs/";
use constant MAX_COMMAND_LENGTH => 100000;
my $cmd_bash = "bash";
my $cmd_source = "source .profile";
sub run_remote_command_with_login
{
my $start_time = time;
my $host = shift;
my $cmd = shift;
my $user = shift;
my $pwd = shift;
my $is_import = 1 if (shift);

if(length($cmd) > MAX_COMMAND_LENGTH)
{
logger(ERROR, "The command will not be run as it is longer than ".MAX_COMMAND_LENGTH." characters");
return 0;
}


logger(DEBUG, "Opening telnet for ".$host." with user $user");

$t = new Net::Telnet (Timeout => TIMEOUT, Errmode => ERRORMODE, Prompt => '/([>\$%~]|Logging out)\s*$/');
$t->open($host);

unless($t->login($user, $pwd)){
logger(WARNING, "Login failed with return value $response");
logger(WARNING, "Login failed to $host with user $user");
return "";
}
$t->max_buffer_length(BUFFER);

my @lines = $t->cmd($cmd_bash);
@lines = $t->cmd($cmd_source);

logger(DEBUG, "Running command: ".$cmd);

if ($is_import)
{
$t->print($cmd);
($prematch, $match) = $t->waitfor('/.*Logging out.*/i');
@lines = split(/\n/, $prematch);
$ok = $t->close;
}
else
{
@lines = $t->cmd($cmd);
$ok = $t->close;
}

if($ok)
{
logger(DEBUG, "Closed telnet for ".$host);
}
else
{
logger(WARNING, "Could not close telnet for ".$host);
logger(WARNING, "Error code: ".$ok);
}

logger(DEBUG, "Output lines are:");
for($i = 0; $i < scalar(@lines); $i++)
{
logger(DEBUG, $lines[$i]);
}
logger(DEBUG, "End of output lines.");

if (not -d OUTPUT_PATH)
{
my $cmd = "mkdir ".OUTPUT_PATH;
`$cmd`;
}
my $out = OUTPUT_PATH.$start_time.".txt";
open(DAT2, ">$out") || die("Could not open file!");
logger(INFO, "Remote command execution finished in ".(time - $start_time)." seconds. (Output: $out)");

for (my $i = 0; $i < scalar(@lines); $i++)
{
print DAT2 $lines[$i]."\n";
}
close(DAT2);

return \@lines;
}

这个模块是为 Telnet 连接到远程服务器而编写的,并且工作正常。但我们有一些 Linux 服务器,他们希望我通过 SSH 连接这些服务器。这不是问题,但在该远程主机中我们想要存档或移动文件。我们在 Archive.pl 中有这样的模块:

sub archive
{
my $cmd_list = "find $source_dir -name \"$log_name_pattern\" -a ! -name \"*.gz\" -a ! -mtime -$archive_interval -a ! -size 0 -a -type f";
my $cmd_gzip = "find $source_dir -name \"$log_name_pattern\" -a ! -name \"*.gz\" -a ! -mtime -$archive_interval -a ! -size 0 -a -type f -exec gzip {} \\;";

Utilities::logger(Utilities::INFO,"Running command: $cmd_list");

my $output = Utilities::run_remote_command_with_login($source_server, $cmd_list, $source_user, get_pwd($source_user));

extract_files(\@$output);

if(scalar(@$output) == 0)
{
Utilities::logger(Utilities::INFO,"No files found to archive.");
}
else
{
Utilities::logger(Utilities::INFO, scalar(@$output)." file(s) will be zipped:");
for(my $i = 0; $i < scalar(@$output); $i++)
{
print $$output[$i];
}

Utilities::logger(Utilities::INFO,"Running command: $cmd_gzip");
if($source_user == "picshot"){
$output = Utilities::run_remote_command_with_login($source_server, $cmd_gzip, $source_user, get_pwd($source_user));
}
else{
$output = Utilities::run_remote_command_with_login($source_server, $cmd_gzip, $source_user, get_pwd($source_user));
}
}
}

sub move
{
my $cmd_filelist = "find $source_dir -name \"$log_name_pattern.gz\" -a ! -mtime -$move_interval -a -type f";
Utilities::logger(Utilities::INFO,"Running command: $cmd_filelist");
my $output = Utilities::run_remote_command_with_login($source_server, $cmd_filelist, $source_user, get_pwd($source_user));

extract_files(\@$output);

if(scalar(@$output) == 0)
{
Utilities::logger(Utilities::INFO,"No files found to move");
}
else
{
Utilities::logger(Utilities::INFO, scalar(@$output)." file(s) will be moved:");
for(my $i = 0; $i < scalar(@$output); $i++)
{
print $$output[$i];
}

if($source_server ne $target_server)
{
my $to_delete = Utilities::run_remote_ftp($source_server, $source_dir, $source_user, $source_user, $target_server, $target_dir, $target_user, $target_user, $output);

if(scalar(@$to_delete) == 0)
{
Utilities::logger(Utilities::WARNING,"FTP put returned no files, keeping source files");
}
else
{
Utilities::logger(Utilities::INFO,"FTP put finished. Removing files returned by PUT");
my $cmd_delete = "rm ";

for(my $i = 0; $i < scalar(@$to_delete); $i++)
{
$$to_delete[$i] = Utilities::trim($$to_delete[$i]);
$cmd_delete = $cmd_delete.$$to_delete[$i]." ";
}
Utilities::logger(Utilities::INFO,"Running command: $cmd_delete");
Utilities::run_remote_command_with_login($source_server, $cmd_delete, $source_user, get_pwd($source_user));
}
}
else
{
my $cmd_move = "mv ";
for(my $i = 0; $i < scalar(@$output); $i++)
{
$$output[$i] = Utilities::trim($$output[$i]);
$cmd_move = $cmd_move." ".$$output[$i];
}
$cmd_move = $cmd_move." ".$target_dir;

# Create target dir if it does not exist.
my $cmd_create_dir = "mkdir -p ".$target_dir;
Utilities::logger(Utilities::INFO,"Running command: $cmd_create_dir");
my $output = Utilities::run_remote_command_with_login($target_server, $cmd_create_dir, $target_user, get_pwd($target_user));

Utilities::logger(Utilities::INFO,"Running command to move files");
Utilities::logger(Utilities::INFO,"Running command: $cmd_move");
$output = Utilities::run_remote_command_with_login($target_server, $cmd_move, $target_user, get_pwd($target_user));
Utilities::check_move_cmd($output);
}
}
}

这两个模块工作正常。他们正在成功归档和移动文件。

我在我想要连接的服务器之间进行了 ssh-keygen rsa 配置。我正在尝试在 perl 脚本上运行它:

my $cmd_gzip = "$source_dir -name \"$log_name_pattern\" -a ! -name \"*.gz\" -a ! -mtime -$archive_interval -a ! -size 0 -a -type f -exec gzip {} \\;";

system("ssh", "$source_user\@$source_server" , "find" , $cmd_gzip);

它成功连接到远程服务器,并列出文件。但是当我想压缩我想要存档的文件时,它不起作用。控制台显示“权限被拒绝”

顶部的存档模块有 extract_files 模块。它是这样的:

sub extract_files
{
Utilities::logger(Utilities::DEBUG,"Entering sub: extract_files");
my $temp = shift;

my $size = scalar(@$temp);
Utilities::logger(Utilities::DEBUG,"Initial array size is $size.");
my $temp_log_name_pattern = $log_name_pattern;
$temp_log_name_pattern =~ s/\*/.*/g;

my $i = 0;
while($i < $size)
{
Utilities::logger(Utilities::DEBUG,"Currently processing: $$temp[$i]. i = $i, size = $size");
# Extract only files from output. " character in second part is used to filter out initial find command that can wrap and exist in the output.
if ($$temp[$i] =~ $temp_log_name_pattern and $$temp[$i] !~ m/.*".*/)
{
Utilities::logger(Utilities::DEBUG,"Matched filename: $$temp[$i]");
$i++;
}
else
{
Utilities::logger(Utilities::DEBUG,"Did not match filename: $$temp[$i]");
splice(@$temp,$i,1);
$size--;
}
}
Utilities::logger(Utilities::DEBUG,"Exiting sub: extract_files");
}

我认为这使得脚本可以工作并避免错误“权限被拒绝”。但它得到一个像这样的参数:

my $output = Utilities::run_remote_command_with_login($source_server, $cmd_list, $source_user, get_pwd($source_user));

extract_files(\@$output);

所以现在我问两件事,

  1. 我不知道这个 run_remote_command_with_login 模块返回什么,所以我无法创建 ssh 连接模块来正确使用所有模块。我如何从系统命令中获得返回?就像 run_remote_command_with_login 模块得到 system("ssh", "$source_user\@$source_server", "find", $cmd_gzip);(我没有写那个模块)

  2. 如果我错了,extract_files() 模块无法避免“权限被拒绝”错误。我该怎么做 ?有什么想法吗。

我希望我如实地说出了我想问的一切。预先感谢您。

最佳答案

您需要验证 ZIPping 的用户帐户是否具有正确的权限。您可能需要打印出用户帐户,在Linux下可以使用id命令来完成。

关于linux - 系统命令返回是什么?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/22532728/

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