bash - $* 在 bash 脚本中意味着什么？

Question

$* 在 bash 脚本中意味着什么？

我尝试在 google 上搜索它，但只找到了 $0、$1 等内容。

Answer 1

从 man 页面:

* Expands to the positional parameters, starting from one. When the expansion occurs within double quotes, it expands to a single word with the value of each parameter separated by the first character of the IFS special variable. That is, "$*" is equivalent to "$1c$2c...", where c is the first character of the value of the IFS variable. If IFS is unset, the parameters are separated by spaces. If IFS is null, the parameters are joined without intervening separators.

因此它相当于所有位置参数，但语义略有不同，具体取决于它是否在引号中。