regex - 使用 grep (或类似的)在第一次匹配后获取字符串

Question

假设我有一些 JSON 文本:

{
    "key1": "value1"
    "key2": "value2"
    "key3": "value3"
    "key4": "value4"
    "key5": "value5"
}
{
    "key1": "value1"
    "key2": "value2"
    "key3": "value3"
    "key4": "value4"
    "key5": "value5"
}

我想要做的是找到“value1”，但只打印“value5”。将会有很多“value5”，但我只想打印它前面有“value1”(这将是一个唯一的字符串)的情况。我无法使用 grep -Ax & -Bx

因为我不想匹配后面的行，而是想打印字符串。

Answer 1

示例文件:

cat t
{
    "key1": "value1"
    "key2": "value2"
    "key3": "value3"
    "key4": "value4"
    "key5": "value5"
}
{
    "key1": "value6"
    "key2": "value2"
    "key3": "value3"
    "key4": "value4"
    "key5": "value5"
}

如果key1=value6，则打印key5中的数据

awk '/key1/ && /value6/ {f=1} f && /key5/ {print $NF;f=0}'
"value5"