php - 如果 columrow 包含名称，则样式表行

Question

我有一个统计表 MySQL输入。

如果 <tr>包含某个名字Hulzense Boys，则表行需要获取#CCCCCC;的背景色

这是我的代码:

if(mysql_num_rows($result) > 0){
        $team = array();
        $ctr = 1;
        while($row = mysql_fetch_array($result)) {

            echo "<table><tr><td class='nummer'>";
            echo $ctr++. '</td><td class="styled-td">';
            echo $row['Team']. '</td><td class="styled-td2">';
            echo $row['Gespeeld']. '</td><td class="styled-td2">';
            echo $row['Gewonnen']. '</td><td class="styled-td2">';
            echo $row['Gelijk']. '</td><td class="styled-td2">';
            echo $row['Verloren']. '</td><td class="styledPUNTEN-td">';
            echo $row['Punten']. '</td><td class="styled-td2">';
            echo $row['DPV']. '</td><td class="styled-td2">';
            echo $row['DPT']. '</td><td class="styled-td2">';
            echo $row['Verschil']. '</td><td class="styled-td2">';
            echo "</td></tr></table>";
            $team = $row['Team'];
            }
    }

这是我测试的输出:

我试过了，但是没用:

    if ($row['Team'] == 'Hulzense Boys') {

    }

希望能帮到你

Answer 1

试试这个:

if(mysql_num_rows($result) > 0){
        $team = array();
        $ctr = 1;
        while($row = mysql_fetch_array($result)) {
            $highlighted = $row['Team'] == "Hulzense Boys" ? "background-color:#ff0" : "";
            echo "<table><tr style=\"$highlighted\"><td class='nummer'>";
            echo $ctr++. '</td><td class="styled-td">';
            echo $row['Team']. '</td><td class="styled-td2">';
            echo $row['Gespeeld']. '</td><td class="styled-td2">';
            echo $row['Gewonnen']. '</td><td class="styled-td2">';
            echo $row['Gelijk']. '</td><td class="styled-td2">';
            echo $row['Verloren']. '</td><td class="styledPUNTEN-td">';
            echo $row['Punten']. '</td><td class="styled-td2">';
            echo $row['DPV']. '</td><td class="styled-td2">';
            echo $row['DPT']. '</td><td class="styled-td2">';
            echo $row['Verschil']. '</td><td class="styled-td2">';
            echo "</td></tr></table>";
            $team = $row['Team'];
            }
    }

或者为 $highlighted 分配一个类名，并在 tr 元素上使用该类。