c - 在 for 循环中重复使用 switch 语句

Question

我正在尝试使用循环来打印出一首重复的歌曲“this old man”第一节是:这位老人，他演奏了一个他在我的拇指上玩小玩意儿这位老人滚回家了

这首歌重复到十次，将两个词用斜体字改变one -> two++ 和 thumb -> 另一件元素，如鞋子、膝盖等。到目前为止，这是我的代码:

#include <cs50.h>
#include <stdio.h>
#include <string.h>

string change1 (int i);
int main (void)
{ 
    for (int i = 1; ; 1 < 11; i++)
    {
        printf ("This old man, he played "); 
        change1(i);
        printf("He played knick-knack on my %s\n\n", s1);
    }

    return 0;
 }

string change1(int i)
{
    string s1;

    switch(i)
    {
        case 1: 
        {
            printf("one\n");
            s1 = "thumb";
        }
            break;
        case 2:
        {
            printf("two\n");
            s1 = "shoe";
        }
            break;
        case 3:
        case 4:
        case 5:
        case 6:
        case 7:
        case 8:
        case 9:
        case 10:
        case 11:
            printf("ill add these cases later");
    }
}

这给我一条错误消息:“控制到达非空函数的末尾”

---

我也遇到了一个未声明的变量 s1 错误，但我在函数中声明了它。

Answer 1

您可以将您的程序简化为实际的 C 程序，而不是 C++

int main (void)
{
    int i;
    char* items[] = {"thumb", "shoe", "", "", "", "", "", "", "", ""};
    char* numbers[] = {"one", "two", "three","four","five","six","seven","eight","nine","ten"};
    for (i = 0; i < 10; i++)
    {
        printf ("This old man, he played %s\n", numbers[i]);    
        printf("He played knick-knack on my %s\n\n", items[i]);
    }
  return 0
}