python - 循环引用在哪里？

Question

我正在编写一些我想编码成 JSON 的 python 类。当我尝试对我的对象进行 jsonify 时，我收到一条错误消息，提示“循环引用”。我想我明白循环引用的含义，但我在我的代码中找不到任何示例。

对象之间的关系(has a/is a)

• 注册有一个
• 注册人有一个
• 地址

代码(python):

class Address:
    def __init__(self, address1, address2, city, state, zip):
        self.address1 = address1
        self.address2 = address2
        self.city = city
        self.state = state
        self.zip = zip

class Signup:
    def __init__(self, registrant, classId, date, time, paid, seatCost, notes, className, seats, groupId, agentName, agentCompany):
        self.registrant = registrant
        self.classId = classId
        self.date = date
        self.time = time
        self.paid = paid
        self.seatCost = seatCost
        self.notes = notes
        self.className = className
        self.seats = seats
        self.groupId = groupId
        self.agentName = agentName
        self.agentCompany = agentCompany

class Registrant:
    def __init__(self, firstName, lastName, address, phone, email):
        self.firstName = firstName
        self.lastName = lastName
        self.address = address
        self.phone = phone
        self.email = email

def scrape(br):
    signups = []

    soup = libStuff.getSoup(br, 'http://thepaintmixer.com/admin/viewdailysignups.php')

    table = soup.find(id='Calendar')
    rows = table.find_all('tr')
    rowNumber = 0
    for row in rows:
        if rowNumber == 0:
            rowNumber = rowNumber + 1
            continue
        cells = row.find_all('td')
        cellNumber = 0
        for cell in cells:
            if cellNumber == 0:
                try:
                    firstName = cell.contents[0]
                except IndexError:
                    firstName = None
            elif cellNumber == 1:
                try:
                    lastName = cell.contents[0]
                except IndexError:
                    lastName = None
            elif cellNumber == 2:
                try:
                    address1 = cell.contents[0]
                except IndexError:
                    address1 = None
            elif cellNumber == 3:
                try:
                    address2 = cell.contents[0]
                except IndexError:
                    address2 = None
            elif cellNumber == 4:
                try:
                    city = cell.contents[0]
                except IndexError:
                    city = None
            elif cellNumber == 5:
                try:
                    state = cell.contents[0]
                except IndexError:
                    state = None
            elif cellNumber == 6:
                try:
                    zip = cell.contents[0]
                except IndexError:
                    zip = None
            elif cellNumber == 7:
                try:
                    phone = cell.contents[0]
                except IndexError:
                    phone = None
            elif cellNumber == 8:
                try:
                    email = cell.contents[0]
                except IndexError:
                    email = None
            elif cellNumber == 9:
                try:
                    classId = cell.contents[0]
                except IndexError:
                    classId = None
            elif cellNumber == 10:
                try:
                    date = cell.contents[0]
                except IndexError:
                    date = None
            elif cellNumber == 11:
                try:
                    time = cell.contents[0]
                except IndexError:
                    time = None
            elif cellNumber == 12:
                try:
                    paid = cell.contents[0]
                except IndexError:
                    paid = None
            elif cellNumber == 13:
                try:
                    seatCost = cell.contents[0]
                except IndexError:
                    seatCost = None
            elif cellNumber == 14:
                try:
                    notes = cell.contents[0]
                except IndexError:
                    notes = None
            elif cellNumber == 15:
                try:
                    className = cell.contents[0]
                except IndexError:
                    className = None
            elif cellNumber == 16:
                try:
                    seats = cell.contents[0]
                except IndexError:
                    seats = None
            elif cellNumber == 17:
                try:
                    groupId = cell.contents[0]
                except IndexError:
                    groupId = None
            elif cellNumber == 18:
                try:
                    agentName = cell.contents[0]
                except IndexError:
                    agentName = None
            elif cellNumber == 19:
                try:
                    agentCompany = cell.contents[0]
                except IndexError:
                    agentCompany = None
            cellNumber = cellNumber + 1

        address = Address(address1, address2, city, state, zip)
        registrant = Registrant(firstName, lastName, address, phone, email)
        signup = Signup(registrant, classId, date, time, paid, seatCost, notes, className, seats, groupId, agentName, agentCompany)
        signups.append(signup)
    return signups
#I then call json.dumps() on that returned list
json.dumps(scrape(br), default=lambda o: o.__dict__)

我的构造函数搞砸了吗？我是否传递了不该传递的东西？

Answer 1

可能的原因是 cell.contents[0]返回一个复杂的 BeautifulSoup 对象而不是纯文本。 BeautifulSoup 对象知道它们的父对象、兄弟对象、解析器类、属性和其他可能共享或循环的对象。

当一个 <td>元素包含内部 html。这在表格中很常见(例如，表格条目可能是粗体或斜体)。

您的问题的可能解决方案是确保使用 BeautifulSoup 的 .text确保您只获取文本而不是内部 BeautifulSoup 元素:

columns = [col.text for col in row.findAll('td')] 

FWIW，这是一种简单的诊断技术，可以查看实际发生的情况。只需修改 json.dumps() 中的默认函数，使其输出可见:

def view_dict(obj):
    print '--------------'
    print 'Type:', obj.__class__
    d = obj.__dict__
    pprint.pprint(d)
    return d

json.dumps(scrape(br), default=view_dict)

循环引用应该会立即弹出。希望这能揭开谜团(因为否则您的代码看起来很好并且没有明确创建循环引用)。