根据 C 中的条件更改指针(星号 1.4 cdr 结构)

Question

如何执行以下操作？ full_agentstring 需要指向 cdr->channel 或 cdr->dstchannel:

....
char *cdr_channel = cdr->channel;
char *cdr_dstchannel = cdr->dstchannel;
char *full_agentstring = NULL;
if(strstr(cdr_channel, agent_pattern) != NULL) {
      *full_agentstring = cdr->channel;
} else if(strstr(cdr_dstchannel, agent_pattern) != NULL) {
      *full_agentstring = cdr->dstchannel;

我也尝试过 full_agentstring = &cdr_dstchannel 但仍然收到警告:

从不兼容的指针类型赋值[默认启用]

Answer 1

if(strstr(cdr_channel, agent_pattern) != NULL) {
      full_agentstring = cdr->channel;
} else if(strstr(cdr_dstchannel, agent_pattern) != NULL) {
      full_agentstring = cdr->dstchannel;

或者如果我没有正确理解你的问题，那么这是第二种方法

char *cdr_channel = cdr->channel;
char *cdr_dstchannel = cdr->dstchannel;
char **full_agentstring = NULL;
if(strstr(cdr_channel, agent_pattern) != NULL) {
      full_agentstring = &cdr->channel;
} else if(strstr(cdr_dstchannel, agent_pattern) != NULL) {
      full_agentstring = &cdr->dstchannel;