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c - 简单二维数组程序中的意外输出

转载 作者:太空宇宙 更新时间:2023-11-04 03:40:34 26 4
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作为家庭作业,我必须创建一个简单的程序,从标准的 52 张卡片组中输出 5 张不同的卡片。

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<time.h>

void deal(char input_array[5][4]);

char deck[52][4]={"AcS","02S","03S","04S","05S","06S","07S","08S","09S","10S","JaS","QuS","KiS",
"AcH","02H","03H","04H","05H","06H","07H","08H","09H","10H","JaH","QuH","KiH","AcD","02D",
"03D","04D","05D","06D","07D","08D","09D","10D","JaD","QuD","KiD","AcC","02C","03C","04C",
"05C","06C","07C","08C","09C","10C","JaC","QuC","KiC"};

main()
{
int index;
char hand[5][4];
deal(hand);

for(index = 0; index < 5; index++){
printf("%s\n", hand[index]);
}
}

void deal(char input_array[5][4])
{
int i, j, randInt, count = 0;
//srand((unsigned int)time(NULL));
srand(time(NULL));

/* outer for loop used to assign 5 cards to array */
for (i = 0; i < 5; i++){

/* random int generated between 0 and 51, so a random card can be picked from the deck array */
randInt = (rand() % 52);

/* inner for loop checks each time whether the card already exists in the input_array. if it exists, count is incremented by 1 */
for(j = 0; j < 5; j++){

if(strcmp(input_array[j], deck[randInt]) == 0){
++count;
}

}

/* after exiting inner for loop, if count is still 0, the card chosen from the deck isn't already in input_array. so it's added to input_array */
if(count == 0){
strcpy(input_array[i], deck[randInt]);
}

}
}

但是一旦我一遍又一遍地运行它,最终我会得到奇怪的/意外的/随机的值(见下面的输出图像)。

http://i.imgur.com/7HBQIwR.jpg

http://i.imgur.com/PgpFoda.jpg

我检查了每一行代码并仔细检查了所有内容。我不知道这里出了什么问题。任何帮助表示赞赏。

最佳答案

您的代码在此处表现出未定义的行为:

if(strcmp(input_array[j], deck [randInt]) == 0){

因为 input_array 没有初始化并且包含“垃圾”值。

要修复它,改变

for(j = 0; j < 5; j++){

for(j = i-1; j >= 0; j--){

同时添加一个 else 部分:

if(count == 0){
strcpy(input_array[i], deck [randInt]);
}
else{
input_array[i][0]='\0';
}

input_array[i][0]='\0'; 完成以 NUL 终止 input_array[i] 以便它被初始化并且 main 中的 printf 不打印奇怪的东西。

关于c - 简单二维数组程序中的意外输出,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29044965/

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