linux - 如何从linux命令 "who"中剪切子字符串

Question

命令who返回登录到服务器的用户列表

[admin@DB01ATK ~]$ who
adm_drodmann pts/3        2015-07-01 08:57 (10.129.12.77)
adm_ssmith   pts/4        2015-07-01 02:11 (10.129.12.76)
adm_kholdman pts/2        2015-06-30 23:08 (10.129.12.45)

重点是分配给变量，用户名($1)的值，其中终端($2)是命令的结果

ps aux | grep screen

Answer 1

提出的问题回答的问题:

PTS=$(awk '{print $7}' <<< $(ps aux | grep screen) )
who | while  read CMD;
   do 
     res=$(awk '{print $2}' <<< "$CMD")
     if [ "$res" = "$PTS" ]
     then 
       echo "logged as $(awk '{print $1}' <<< "$CMD")"
     fi  
   done;

:-)