python - 在 python 上绘制带有 turtle 图形的条形码

Question

我知道用 Python 做很多事情有疯狂的捷径，这就是我在 CIS 入门类(class)的这个项目中遇到麻烦的地方。我已经搜索了我的问题的变体，但没有运气......所以:

该项目是让我们的“turtle ”使用将输入命令行的 ZIP 绘制条形码。我完成了很多结构性工作，即:对特定数字进行编码并告诉 turtle 为特定数字绘制条形图多长时间。但是，现在我坚持编写 for 循环以实际将这两个部分放在一起并获取绘制条形码的程序。

这是我所拥有的:

import argparse # Used in main program to obtain 5-digit ZIP code from command
            # line
import time # Used in main program to pause program before exit
import turtle   # Used in your function to print the bar code

## Constants used by this program
SLEEP_TIME = 30 # number of seconds to sleep after drawing the barcode
ENCODINGS = [[1, 1, 0, 0, 0],   # encoding for '0'
         [0, 0, 0, 1, 1],   # encoding for '1'
         [0, 0, 1, 0, 1],   # encoding for '2'
         [0, 0, 1, 1, 0],   # encoding for '3'
         [0, 1, 0, 0, 1],   # encoding for '4'
         [0, 1, 0, 1, 0],   # encoding for '5'
         [0, 1, 1, 0, 0],   # encoding for '6'
         [1, 0, 0, 0, 1],   # encoding for '7'
         [1, 0, 0, 1, 0],   # encoding for '8'
         [1, 0, 1, 0, 0]    # encoding for '9'
        ]
SINGLE_LENGTH = 25  # length of a short bar, long bar is twice as long

def compute_check_digit(digits):

    sum = 0
    for i in range(len(digits)):
        sum = sum + digits[i]
    check_digit = 10 - (sum % 10)
    if (check_digit == 10):
        check_digit = 0
    return check_digit


def draw_bar(my_turtle, digit):
    my_turtle.left(90)
    if digit == 0:
        length = SINGLE_LENGTH
    else:
        length = 2 * SINGLE_LENGTH
    my_turtle.forward(length)
    my_turtle.up()
    my_turtle.backward(length)
    my_turtle.right(90)
    my_turtle.forward(10)
    my_turtle.down()


def draw_zip(my_turtle, zip):
    # WHAT DO I DO 
    print("My code to draw the barcode needs to replace this print statement")

def main():
    parser = argparse.ArgumentParser()
    parser.add_argument("ZIP", type=int)
    args = parser.parse_args()
    zip = args.ZIP
    if zip <= 0 or zip > 99999:
        print("zip must be > 0 and < 100000; you provided", zip)
    else:
        my_turtle = turtle.Turtle()
        draw_zip(my_turtle, zip)
        time.sleep(SLEEP_TIME)

if __name__ == "__main__":
    main()

开始和结束时的argparse/parser 东西是我们开始每个项目时给我们的。

我知道下一行在某些地方会有帮助，我查看了 map 功能，我知道我需要将编码从字符串转换为整数。

map (列表，海峡( zip ))

谢谢!

Answer 1

您需要遍历 zip 的数字。对于每个数字，您将遍历 5 个条。

for str_digit in str(zip):
    digit = int(str_digit)
    for bar_bit in ENCODINGS[digit]:
        draw_bar(my_turtle, bar_bit)
        <move turtle to next bar's starting point>

我希望这对您来说是可以理解的。您可以使用各种 Python 技术来缩短代码，但这很容易理解。