python - XML 标记文本到字符串忽略子标记但包括它们的文本

Question

我正在解析如下所示的 XML 数据:

<title-group><article-title>Leucine to proline substitution by SNP at position 197 in Caspase-9 gene expression leads to neuroblastoma: a bioinformatics analysis</article-title></title-group>

有时虽然里面有斜体标签:

<title-group><article-title><italic>Interferon regulatory factor 5</italic> genetic variants are associated with cardiovascular disease in patients with rheumatoid arthritis</article-title></title-group>

以下 python 代码返回正确连接的标题字符串，但前提是斜体标记不在标题的开头(如上面的代码所示):

    #Get titles
    for node in tree.iter('title-group'):
        for subnode in node.iter('article-title'):
            try:
                title = remove_control_characters(subnode.text)
                if len(title) == 0:
                    for subsubnode in node.iter('italic'):
                        italic = subsubnode.text 
                        tail = remove_control_characters(subsubnode.tail)
                        title += italic + tail  
                        title = str(title)  
                        break                       
            except:
                continue
            for subsubnode in node.iter('italic'):
                italic = subsubnode.text 
                tail = remove_control_characters(subsubnode.tail)
                title += italic + tail  
                title = str(title)  

当斜体标签位于字符串的开头时，不返回任何内容。

有没有更简单的方法(不包括lxml)可以使用？或者，如果您可以建议对 Python 代码进行更改，我们也将不胜感激。欢迎提出建议，祝您有愉快的一天。

编辑 [已解决]

#Get titles
    for node in tree.iter('title-group'):
        for subnode in node.iter('article-title'):
            whole = subnode.itertext()
            for parts in whole:
                title += parts
    print(remove_control_characters(title))

Answer 1

使用 itertext() <article-title> 上的方法标记，你应该没问题。