- android - 多次调用 OnPrimaryClipChangedListener
- android - 无法更新 RecyclerView 中的 TextView 字段
- android.database.CursorIndexOutOfBoundsException : Index 0 requested, 光标大小为 0
- android - 使用 AppCompat 时,我们是否需要明确指定其 UI 组件(Spinner、EditText)颜色
我正在为做练习题的测试而学习,似乎无法让我的链表与递归地从链表中删除元素的函数一起正常工作。下面是我的完整代码,如果您看到我可以改进其他方法的任何方法,请告诉我。谢谢! :)
/*
Q1:
Try implementing the functions shown in class on your own:
check: node creation
check: insertion at the end of a linked list,
check: insertion at the head of a linked list,
check: a list printing function.
Q2:
check: Write a recursive printList() function.
Q3:
check: Write a recursive tailInsert() function.
Q4:
check: Write a function that inserts nodes at the beginning of the linked list.
Q5:
check: Write a recursive function that prints a linked list in reverse order.
The function signature is: void printReverse(node *head);
Q6:
- Write an iterative destroyList() function that frees all the nodes in a linked list.
Q7:
- Now implement destroyList() recursively.
Q8:
- Write a function that deletes the nth element from a linked list.
If the linked list doesn't even have n nodes, don't delete any of them.
The function signature is: node *deleteNth(node *head, int n).
- Try implementing the function iteratively and recursively.
- (In terms of how to interpret n, you can start counting your nodes from zero or one; your choice.)
Q9:
- Write a function that deletes every other element in a linked list.
- (Try writing it both ways: one where it starts deleting at the head of the list,
- and one where it starts deleting at the element just after the head of the list.)
- Can you write this both iteratively and recursively?
Q10:
- Write a function that deletes all even integers from a linked list.
Q11:
- Write a function that takes a sorted linked list and an element to be inserted into that linked list,
and inserts the element in sorted order.
The function signature is: node *insertSorted(node *head, int n);
Q12:
- One of the problems with the first insertNode() function from today is that it
requires us to call it using head = insertNode(head, i).
That's a bit dangerous, because we could forget the "head =" part very easily.
Re-write the function so that it takes a pointer to head,
thereby allowing it to directly modify the contents of head without any need for a return value.
The function signature is: void insertNode(node **head, int data).
The function will be called using insertNode(&head, i).
*/
//come back to
#include <stdio.h>
#include <stdlib.h>
// Basic linked list node struct; contains 'data' and 'next' pointer.
// What happens if we type "node *next" instead of "struct node *next"?
typedef struct node
{
// data field
int data;
// the next node in the list
struct node *next;
} node;
// Allocate a new node. Initialize its fields. Return the pointer.
// We call this from our insertion functions.
node *createNode(int data)
{
node *ptr = NULL;
ptr = malloc(sizeof(node));
if(ptr == NULL)
{
printf("space could not be allocated\n");
return NULL;
}
ptr->data = data;
ptr->next = NULL;
return ptr;
}
// Insert into the end of the linked list. Return the head of the linked list.
// (What is the order (Big-Oh) of this function?)
node *insertNode(node *head, int data)
{
node *temp;
if (head == NULL)
return createNode(data);
for(temp = head; temp->next != NULL; temp = temp->next)
;
temp->next = createNode(data);
return head;
}
node *insertNodeFront(node *head, int data)
{
node *temp;
if(head == NULL)
return createNode(data);
temp = createNode(data);
temp->next = head;
return temp;
}
// Simple function to print the contents of a linked list.
void printList(node *head)
{
if (head == NULL)
{
printf("Empty List\n");
return;
}
for(; head != NULL; head = head->next)
printf("%d ", head->data);
printf("\n");
}
void printListRecursiveHelper(node *head)
{
if (head == NULL)
return;
printf("%d%c", head->data, (head->next == NULL) ? '\n' : ' ');
printListRecursiveHelper(head->next);
}
void printListRecursive(node *head)
{
if (head == NULL)
{
printf("empty list\n");
return;
}
printListRecursiveHelper(head);
}
// Q3: - Write a recursive tailInsert() function.
node *tailInsert(node *head, int data)
{
if(head->next == NULL)
{
node *temp;
temp = createNode(data);
temp->next = NULL;
head->next = temp;
return temp;
}
return tailInsert(head->next, data);
}
//Q5: Write a recursive function that prints a linked list in reverse order.
void printReverse(node *head)
{
if (head == NULL)
return;
printReverse(head->next);
printf("%d ", head->data);
}
// Q6: - Write an iterative destroyList() function that frees all the nodes in a linked list.
// Got code from internet, memorize it
/* Function to delete the entire linked list */
void destroyList (struct node** head)
{
struct node* current = *head;
struct node* next;
while (current != NULL)
{
next = current->next;
free(current);
current = next;
}
*head = NULL;
}
//Q7: - Now implement destroyList() recursively.
// Look up online, need to examine why it deson't work
node *destroyListRecursive(node *head)
{
if ( head == NULL)
return NULL;
destroyListRecursive(head->next);
free(head);
}
int main(void)
{
int i, r;
// The head of our linked list. If we don't initialize it to NULL, our
// insertNode() function might segfault.
node *head = NULL;
srand(time(NULL));
// Populate the linked list with random integers. We are inserting into the
// head of the list each time.
for (i = 0; i < 10; i++)
{
printf("Inserting %d...\n", r = rand() % 20 + 1);
head = insertNode(head, r);
}
head = insertNodeFront(head, 1);
tailInsert(head, 5);
// Print the linked list.
printList(head);
printf("\n");
printReverse(head);
printf("\n\n");
// Print the linked list using our recursive function.
printListRecursive(head);
//destroyList(&head);
head = destroyListRecursive(head);
printList(head);
system("PAUSE");
return 0;
}
最佳答案
这是基于我的 [和其他人] 的热门评论,但这是有效的 [很抱歉发布整个程序,只是 main
中的一行更改和函数的重写]:
/*
Q1:
Try implementing the functions shown in class on your own:
check: node creation
check: insertion at the end of a linked list,
check: insertion at the head of a linked list,
check: a list printing function.
Q2:
check: Write a recursive printList() function.
Q3:
check: Write a recursive tailInsert() function.
Q4:
check: Write a function that inserts nodes at the beginning of the linked list.
Q5:
check: Write a recursive function that prints a linked list in reverse order.
The function signature is: void printReverse(node *head);
Q6:
- Write an iterative destroyList() function that frees all the nodes in a linked list.
Q7:
- Now implement destroyList() recursively.
Q8:
- Write a function that deletes the nth element from a linked list.
If the linked list doesn't even have n nodes, don't delete any of them.
The function signature is: node *deleteNth(node *head, int n).
- Try implementing the function iteratively and recursively.
- (In terms of how to interpret n, you can start counting your nodes from zero or one; your choice.)
Q9:
- Write a function that deletes every other element in a linked list.
- (Try writing it both ways: one where it starts deleting at the head of the list,
- and one where it starts deleting at the element just after the head of the list.)
- Can you write this both iteratively and recursively?
Q10:
- Write a function that deletes all even integers from a linked list.
Q11:
- Write a function that takes a sorted linked list and an element to be inserted into that linked list,
and inserts the element in sorted order.
The function signature is: node *insertSorted(node *head, int n);
Q12:
- One of the problems with the first insertNode() function from today is that it
requires us to call it using head = insertNode(head, i).
That's a bit dangerous, because we could forget the "head =" part very easily.
Re-write the function so that it takes a pointer to head,
thereby allowing it to directly modify the contents of head without any need for a return value.
The function signature is: void insertNode(node **head, int data).
The function will be called using insertNode(&head, i).
*/
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
// Basic linked list node struct; contains 'data' and 'next' pointer.
// What happens if we type "node *next" instead of "struct node *next"?
typedef struct node {
// data field
int data;
// the next node in the list
struct node *next;
} node;
// Allocate a new node. Initialize its fields. Return the pointer.
// We call this from our insertion functions.
node *
createNode(int data)
{
node *ptr = NULL;
ptr = malloc(sizeof(node));
if (ptr == NULL) {
printf("space could not be allocated\n");
return NULL;
}
ptr->data = data;
ptr->next = NULL;
return ptr;
}
// Insert into the end of the linked list. Return the head of the linked list.
// (What is the order (Big-Oh) of this function?)
node *
insertNode(node * head, int data)
{
node *temp;
if (head == NULL)
return createNode(data);
for (temp = head; temp->next != NULL; temp = temp->next);
temp->next = createNode(data);
return head;
}
node *
insertNodeFront(node * head, int data)
{
node *temp;
if (head == NULL)
return createNode(data);
temp = createNode(data);
temp->next = head;
return temp;
}
// Simple function to print the contents of a linked list.
void
printList(node * head)
{
if (head == NULL) {
printf("Empty List\n");
return;
}
for (; head != NULL; head = head->next)
printf("%d ", head->data);
printf("\n");
}
void
printListRecursiveHelper(node * head)
{
if (head == NULL)
return;
printf("%d%c", head->data, (head->next == NULL) ? '\n' : ' ');
printListRecursiveHelper(head->next);
}
void
printListRecursive(node * head)
{
if (head == NULL) {
printf("empty list\n");
return;
}
printListRecursiveHelper(head);
}
// Q3: - Write a recursive tailInsert() function.
node *
tailInsert(node * head, int data)
{
if (head->next == NULL) {
node *temp;
temp = createNode(data);
temp->next = NULL;
head->next = temp;
return temp;
}
return tailInsert(head->next, data);
}
// Q5: Write a recursive function that prints a linked list in reverse order.
void
printReverse(node * head)
{
if (head == NULL)
return;
printReverse(head->next);
printf("%d ", head->data);
}
// Q6: - Write an iterative destroyList() function that frees all the nodes in a linked list.
// Got code from internet, memorize it
/* Function to delete the entire linked list */
void
destroyList(struct node **head)
{
struct node *current = *head;
struct node *next;
while (current != NULL) {
next = current->next;
free(current);
current = next;
}
*head = NULL;
}
// Q7: - Now implement destroyList() recursively.
// Look up online, need to examine why it deson't work
node *
destroyListRecursive(node * head)
{
if (head != NULL) {
destroyListRecursive(head->next);
free(head);
}
return NULL;
}
int
main(void)
{
int i,
r;
// The head of our linked list. If we don't initialize it to NULL, our
// insertNode() function might segfault.
node *head = NULL;
srand(time(NULL));
// Populate the linked list with random integers. We are inserting into the
// head of the list each time.
for (i = 0; i < 10; i++) {
printf("Inserting %d...\n", r = rand() % 20 + 1);
head = insertNode(head, r);
}
head = insertNodeFront(head, 1);
tailInsert(head, 5);
// Print the linked list.
printList(head);
printf("\n");
printReverse(head);
printf("\n\n");
// Print the linked list using our recursive function.
printListRecursive(head);
// destroyList(&head);
head = destroyListRecursive(head);
printList(head);
system("PAUSE");
return 0;
}
关于c - 在c中递归地从链表中删除元素时的无限链接循环,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/42796871/
我需要将文本放在 中在一个 Div 中,在另一个 Div 中,在另一个 Div 中。所以这是它的样子: #document Change PIN
奇怪的事情发生了。 我有一个基本的 html 代码。 html,头部, body 。(因为我收到了一些反对票,这里是完整的代码) 这是我的CSS: html { backgroun
我正在尝试将 Assets 中的一组图像加载到 UICollectionview 中存在的 ImageView 中,但每当我运行应用程序时它都会显示错误。而且也没有显示图像。 我在ViewDidLoa
我需要根据带参数的 perl 脚本的输出更改一些环境变量。在 tcsh 中,我可以使用别名命令来评估 perl 脚本的输出。 tcsh: alias setsdk 'eval `/localhome/
我使用 Windows 身份验证创建了一个新的 Blazor(服务器端)应用程序,并使用 IIS Express 运行它。它将显示一条消息“Hello Domain\User!”来自右上方的以下 Ra
这是我的方法 void login(Event event);我想知道 Kotlin 中应该如何 最佳答案 在 Kotlin 中通配符运算符是 * 。它指示编译器它是未知的,但一旦知道,就不会有其他类
看下面的代码 for story in book if story.title.length < 140 - var story
我正在尝试用 C 语言学习字符串处理。我写了一个程序,它存储了一些音乐轨道,并帮助用户检查他/她想到的歌曲是否存在于存储的轨道中。这是通过要求用户输入一串字符来完成的。然后程序使用 strstr()
我正在学习 sscanf 并遇到如下格式字符串: sscanf("%[^:]:%[^*=]%*[*=]%n",a,b,&c); 我理解 %[^:] 部分意味着扫描直到遇到 ':' 并将其分配给 a。:
def char_check(x,y): if (str(x) in y or x.find(y) > -1) or (str(y) in x or y.find(x) > -1):
我有一种情况,我想将文本文件中的现有行包含到一个新 block 中。 line 1 line 2 line in block line 3 line 4 应该变成 line 1 line 2 line
我有一个新项目,我正在尝试设置 Django 调试工具栏。首先,我尝试了快速设置,它只涉及将 'debug_toolbar' 添加到我的已安装应用程序列表中。有了这个,当我转到我的根 URL 时,调试
在 Matlab 中,如果我有一个函数 f,例如签名是 f(a,b,c),我可以创建一个只有一个变量 b 的函数,它将使用固定的 a=a1 和 c=c1 调用 f: g = @(b) f(a1, b,
我不明白为什么 ForEach 中的元素之间有多余的垂直间距在 VStack 里面在 ScrollView 里面使用 GeometryReader 时渲染自定义水平分隔线。 Scrol
我想知道,是否有关于何时使用 session 和 cookie 的指南或最佳实践? 什么应该和什么不应该存储在其中?谢谢! 最佳答案 这些文档很好地了解了 session cookie 的安全问题以及
我在 scipy/numpy 中有一个 Nx3 矩阵,我想用它制作一个 3 维条形图,其中 X 轴和 Y 轴由矩阵的第一列和第二列的值、高度确定每个条形的 是矩阵中的第三列,条形的数量由 N 确定。
假设我用两种不同的方式初始化信号量 sem_init(&randomsem,0,1) sem_init(&randomsem,0,0) 现在, sem_wait(&randomsem) 在这两种情况下
我怀疑该值如何存储在“WORD”中,因为 PStr 包含实际输出。? 既然Pstr中存储的是小写到大写的字母,那么在printf中如何将其给出为“WORD”。有人可以吗?解释一下? #include
我有一个 3x3 数组: var my_array = [[0,1,2], [3,4,5], [6,7,8]]; 并想获得它的第一个 2
我意识到您可以使用如下方式轻松检查焦点: var hasFocus = true; $(window).blur(function(){ hasFocus = false; }); $(win
我是一名优秀的程序员,十分优秀!