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cURL 终端命令成功执行,而 libcurl 程序没有

转载 作者:太空宇宙 更新时间:2023-11-04 03:23:18 25 4
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#include <curl/curl.h>

int main(int argc, char *argv[])
{
CURLcode ret;
CURL *hnd;
struct curl_slist *slist1;

slist1 = NULL;
slist1 = curl_slist_append(slist1, "reciever@gmail.com");

hnd = curl_easy_init();
curl_easy_setopt(hnd, CURLOPT_INFILESIZE_LARGE, (curl_off_t)179);
curl_easy_setopt(hnd, CURLOPT_URL, "smtps://smtp.gmail.com:465/mail.txt");
curl_easy_setopt(hnd, CURLOPT_UPLOAD, 1L);
curl_easy_setopt(hnd, CURLOPT_USERPWD, "sender@gmail.com:senderPass");
curl_easy_setopt(hnd, CURLOPT_USERAGENT, "curl/7.47.0");
curl_easy_setopt(hnd, CURLOPT_MAXREDIRS, 50L);
curl_easy_setopt(hnd, CURLOPT_SSL_VERIFYPEER, 0L);
curl_easy_setopt(hnd, CURLOPT_SSL_VERIFYHOST, 0L);
curl_easy_setopt(hnd, CURLOPT_USE_SSL, (long)CURLUSESSL_ALL);
curl_easy_setopt(hnd, CURLOPT_TCP_KEEPALIVE, 1L);
curl_easy_setopt(hnd, CURLOPT_MAIL_FROM, "sender@gmail.com");
curl_easy_setopt(hnd, CURLOPT_MAIL_RCPT, slist1);
curl_easy_setopt(hnd, CURLOPT_VERBOSE, 1L);

ret = curl_easy_perform(hnd);

curl_easy_cleanup(hnd);
hnd = NULL;
curl_slist_free_all(slist1);
slist1 = NULL;

return (int)ret;
}

上面的 libcurl 代码是通过命令行使用以下命令生成的:

curl --url 'smtps://smtp.gmail.com:465' --ssl-reqd --mail-from 'sender@gmail.com' --mail-rcpt 'receiver@gmail.com' --upload-file mail.txt --user 'sender@gmail.com:senderPass' --insecure --libcurl -myCode.c

虽然命令

curl --url 'smtps://smtp.gmail.com:465' --ssl-reqd --mail-from 'sender@gmail.com' --mail-rcpt 'receiver@gmail.com' --upload-file mail.txt --user 'sender@gmail.com:senderPass' --insecure

邮件发送成功,为什么myCode.c发送邮件失败?详细选项的输出在

之后停止响应
< 354 Go ahead [somecharacters].43 -gsmtp

mail.txt 文件是:

From: "I am Sender" <sender@gmail.com>
To: "I am Receiver" <receiver@gmail.com>
Subject: This is a test

Hi,
I’m sending this mail with curl through my gmail account.
Bye!

最佳答案

您必须使用 CURLOPT_READDATA 指定要读取的文件的文件描述符:

curl_easy_setopt(hnd, CURLOPT_READDATA, fd);

整个代码看起来像:

#include <curl/curl.h>

int main(int argc, char *argv[])
{
CURLcode ret;
CURL *hnd;
struct curl_slist *slist1;

slist1 = NULL;
slist1 = curl_slist_append(slist1, "reciever@gmail.com");

FILE *fd;

fd = fopen("mail.txt", "rb");

if(!fd)
return 1;

hnd = curl_easy_init();
curl_easy_setopt(hnd, CURLOPT_INFILESIZE_LARGE, (curl_off_t)179);
curl_easy_setopt(hnd, CURLOPT_URL, "smtps://smtp.gmail.com:465/mail.txt");
curl_easy_setopt(hnd, CURLOPT_UPLOAD, 1L);

curl_easy_setopt(hnd, CURLOPT_READDATA, fd);

curl_easy_setopt(hnd, CURLOPT_USERPWD, "sender@gmail.com:senderPass");
curl_easy_setopt(hnd, CURLOPT_USERAGENT, "curl/7.47.0");
curl_easy_setopt(hnd, CURLOPT_MAXREDIRS, 50L);
curl_easy_setopt(hnd, CURLOPT_SSL_VERIFYPEER, 0L);
curl_easy_setopt(hnd, CURLOPT_SSL_VERIFYHOST, 0L);
curl_easy_setopt(hnd, CURLOPT_USE_SSL, (long)CURLUSESSL_ALL);
curl_easy_setopt(hnd, CURLOPT_TCP_KEEPALIVE, 1L);
curl_easy_setopt(hnd, CURLOPT_MAIL_FROM, "sender@gmail.com");
curl_easy_setopt(hnd, CURLOPT_MAIL_RCPT, slist1);
curl_easy_setopt(hnd, CURLOPT_VERBOSE, 1L);

ret = curl_easy_perform(hnd);

curl_easy_cleanup(hnd);
hnd = NULL;
curl_slist_free_all(slist1);
slist1 = NULL;

return (int)ret;
}

关于cURL 终端命令成功执行,而 libcurl 程序没有,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43449624/

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