Python根据值从字典列表中删除重复项

Question

我有字典列表

vals = [
         {'tmpl_id': 67,  'qty_available': -3.0, 'product_id': 72, 'product_qty': 1.0},     
         {'tmpl_id': 67,  'qty_available': 5.0, 'product_id': 71, 'product_qty': 1.0}
         {'tmpl_id': 69,  'qty_available': 10.0, 'product_id': 74, 'product_qty': 1.0}
       ]

from operator import itemgetter
getvals = operator.itemgetter('tmpl_id')

val.sort(key=getvals)

result = []

for k, g in itertools.groupby(val, getvals):

    result.append(g.next())

val[:] = result

我想删除重复值 (tmpl_id) 并且还基于 qty_available 较小或负数

输出如下:

vals = [
          {'tmpl_id': 67,  'qty_available': 5.0, 'product_id': 71, 'product_qty': 1.0}
          {'tmpl_id': 69,  'qty_available': 10.0, 'product_id': 74, 'product_qty': 1.0}
       ]

Answer 1

from collections import Counter

vals = [{'tmpl_id': 67,  'qty_available': -3.0, 'product_id': 72, 'product_qty': 1.0},
        {'tmpl_id': 67,  'qty_available': 5.0, 'product_id': 71, 'product_qty': 1.0},
        {'tmpl_id': 69,  'qty_available': 10.0, 'product_id': 74, 'product_qty': 1.0},]

k = [x['tmpl_id'] for x in vals]

new_vals=[]

for i in Counter(k):
    all = [x for x in vals if x['tmpl_id']==i]
    new_vals.append(max(all, key=lambda x: x['qty_available']))

>>> new_vals
[
    {'product_qty': 1.0, 'qty_available': 5.0, 'tmpl_id': 67, 'product_id': 71}, 
    {'product_qty': 1.0, 'qty_available': 10.0, 'tmpl_id': 69, 'product_id': 74}
]