Python:有没有更有效的方法来反复检查鼠标？

Question

我目前在 Mac 上运行 Python 3.5，我似乎无法找到一种方法来提高我的代码的效率。

总而言之，我目前正在制作一个命运之轮游戏(或者基本上是刽子手)，并且我拥有它以便当用户点击一个字母时它会检查该字母是否在单词中等。

有没有比编写 26 个 if 语句并每次检查坐标更好的方法？是否有更有效的方法使用 if 语句检查坐标？

while True:
    mouse = win.getMouse()
    if 35 < mouse.x < 65 and 85 < mouse.y < 115:
        ans = "a"
        break
    elif 65 < mouse.x < 95 and 85 < mouse.y < 115:
        ans = "b"
        break
    elif 95 < mouse.x < 125 and 85 < mouse.y < 115:
        ans = "c"
        break
    elif 125 < mouse.x < 155 and 85 < mouse.y < 115:
        ans = "d"
        break
    elif 155 < mouse.x < 185 and 85 < mouse.y < 115:
        ans = "e"
        break
    elif 185 < mouse.x < 215 and 85 < mouse.y < 115:
        ans = "f"
        break
    elif 215 < mouse.x < 245 and 85 < mouse.y < 115:
        ans = "g"
        break
    elif 245 < mouse.x < 275 and 85 < mouse.y < 115:
        ans = "h"
        break
    elif 275 < mouse.x < 305 and 85 < mouse.y < 115:
        ans = "i"
        break
    elif 305 < mouse.x < 335 and 85 < mouse.y < 115:
        ans = "j"
        break
    elif 35 < mouse.x < 65 and 115 < mouse.y < 145:
        ans = "k"
        break
    elif 65 < mouse.x < 95 and 115< mouse.y < 145:
        ans = "l"
        break
    elif 95 < mouse.x < 125 and 115 < mouse.y < 145:
        ans = "m"
        break
    elif 125 < mouse.x < 155 and 115 < mouse.y < 145:
        ans = "n"
        break
    elif 155 < mouse.x < 185 and 115 < mouse.y < 145:
        ans = "o"
        break
    elif 185 < mouse.x < 215 and 115 < mouse.y < 145:
        ans = "p"
        break
    elif 215 < mouse.x < 245 and 115 < mouse.y < 145:
        ans = "q"
        break
    elif 245 < mouse.x < 275 and 115 < mouse.y < 145:
        ans = "r"
        break
    elif 275 < mouse.x < 305 and 115 < mouse.y < 145:
        ans = "s"
        break
    elif 305 < mouse.x < 335 and 115 < mouse.y < 145:
        ans = "t"
        break
    elif 35 < mouse.x < 65 and 145 < mouse.y < 175:
        ans = "u"
        break
    elif 65 < mouse.x < 95 and 145 < mouse.y < 175:
        ans = "v"
        break
    elif 95 < mouse.x < 125 and 145 < mouse.y < 175:
        ans = "w"
        break
    elif 125 < mouse.x < 155 and 145 < mouse.y < 175:
        ans = "x"
        break
    elif 155 < mouse.x < 185 and 145 < mouse.y < 175:
        ans = "y"
        break
    elif 185 < mouse.x < 215 and 145 < mouse.y < 175:
        ans = "z"
        break

Answer 1

作为使用计算与多个 if 语句的简单解决方案:

import string

while True:
    mouse = win.getMouse()
    x, xr = divmod(mouse.x-35, 30)
    y, yr = divmod(mouse.y-85, 30) 
    if not(0 <= x < 10 and 0 <= y < 3):   # Guard values
        continue
    if xr == 0 or yr == 0:                # Gridlines?
        continue
    try:
        ans = string.ascii_lowercase[10*y+x]
        break
    except IndexError:
        pass

例如mouse(x=102, y=143) 会返回 'm'