node.js - 如何在没有 "npm command"的情况下运行 "run"(即 "npm command"而不是 "npm run command")？

Question

我的package.json定义:

    ...
    "scripts": {
        "start": "node scripts/start.js",
        "build": "node scripts/build.js",
        "test": "node scripts/test.js",
        "debug": "node --inspect-brk=9229 scripts/start.js"
    },
    ...

两者npm start和npm test作为npm run start和npm run test分别。然而，npm build不:

$ npm build
npm WARN build `npm build` called with no arguments. Did you mean to `npm run-script build`?

我需要输入run之间npm和build ，即npm run build .

npm debug 也是如此，尽管输出与 npm build 的输出不同:

$ npm debug

Usage: npm <command>

where <command> is one of:
    access, adduser, audit, bin, bugs, c, cache, ci, cit,
    clean-install, clean-install-test, completion, config,
    create, ddp, dedupe, deprecate, dist-tag, docs, doctor,
    edit, explore, get, help, help-search, hook, i, init,
    install, install-ci-test, install-test, it, link, list, ln,
    login, logout, ls, org, outdated, owner, pack, ping, prefix,
    profile, prune, publish, rb, rebuild, repo, restart, root,
    run, run-script, s, se, search, set, shrinkwrap, star,
    stars, start, stop, t, team, test, token, tst, un,
    uninstall, unpublish, unstar, up, update, v, version, view,
    whoami

当然，好像是因为start和test两者都属于 where <command> is one of:列表。

但我想知道，有没有办法告诉 npm运行任意command喜欢 npm build或npm debug甚至npm my_command只是使用 npm build/npm debug/npm my_command ？

这只是我的好奇心，所以我才问。

感谢您的关注。

Answer 1

很抱歉，但直接不可能:(

我想，您可以克隆 npm 存储库并添加您自己的脚本。

之后您将能够像 npm my_awesome_command

一样启动它