javascript - 如何在nodejs中执行顺序基本命令？

Question

我需要在nodejs中顺序运行4个bash命令。

set +o history
sed -i 's/&& !this.peekStartsWith('\/\/')/ /g' dist/vendor.bundle.js
sed -i 's/&& !this.peekStartsWith('\/\/')/ /g' dist/vendor.bundle.js.map
set -o history

如何实现这一目标？或者是否可以添加到 npm 脚本中？

Answer 1

要扩展@melc的答案，按顺序执行请求，您可以这样做:

const {promisify} = require('util');
const {exec} = require('child_process');
const execAsync = promisify(exec);

const sequentialExecution = async (...commands) => {
  if (commands.length === 0) {
    return 0;
  }

  const {stderr} = await execAsync(commands.shift());
  if (stderr) {
    throw stderr;
  }

  return sequentialExecution(...commands);
}

// Will execute the commands in series
sequentialExecution(
  "set +o history",
  "sed -i 's/&& !this.peekStartsWith('\/\/')/ /g' dist/vendor.bundle.js",
  "sed -i 's/&& !this.peekStartsWith('\/\/')/ /g' dist/vendor.bundle.js.map",
  "set -o history",
);

或者，如果您不关心 stdout/sterr，则可以使用以下一行:

const commands = [
  "set +o history",
  "sed -i 's/&& !this.peekStartsWith('\/\/')/ /g' dist/vendor.bundle.js",
  "sed -i 's/&& !this.peekStartsWith('\/\/')/ /g' dist/vendor.bundle.js.map",
  "set -o history",
];

await commands.reduce((p, c) => p.then(() => execAsync(c)), Promise.resolve());