javascript - 如何包装emitter.on(eventName)？

Question

const myEmitter = new MyEmitter();
myEmitter.on('event', (a) => {
  console.log('an event occurred! ' + a);
});
myEmitter.emit('event', "a");

我该如何改变

myEmitter.on('event', (a) => {
   console.log('an event occurred! ' + a);
});

类似于

onEvent((a) => console.log('an event occurred! ' + a))

我想在 myEmitter.on('event') 周围有一个包装器，所以我的 onEvent 本质上只是调用 myEmitter.on('event')。这可能吗？

Answer 1

const onEvent = cb => myEmitter.on('event', cb);

如果您想处理不同的事件，还可以执行以下操作:

const on = (event, cb) => myEmitter.on(event, cb);
on('event', () => console.log('an event occurred!'));