python - 如何使用 pyinstaller 打包 python flask_socketio 应用程序

Question

我尝试了官方的演示代码:

#test.py
from flask import Flask, render_template
from flask_socketio import SocketIO

app = Flask(__name__)
app.config['SECRET_KEY'] = 'secret!'
socketio = SocketIO(app)

if __name__ == '__main__':
    socketio.run(app)

它运行良好，但是当打包时:

pyinstaller --onefile test.py

然后运行test.exe，我得到:

Z:\test\dist>test2.exe
Traceback (most recent call last):
  File "<string>", line 6, in <module>
  File "site-packages\flask_socketio\__init__.py", line 119, in __init__
  File "site-packages\flask_socketio\__init__.py", line 144, in init_app
  File "site-packages\socketio\server.py", line 72, in __init__
  File "site-packages\engineio\server.py", line 100, in __init__
ValueError: Invalid async_mode specified
test2 returned -1

有什么我想念的吗？

Answer 1

将“engineio.async_gevent”添加到规范文件中的 hiddenimports。您可以引用:https://github.com/miguelgrinberg/python-socketio/issues/35