python - 使用 subprocess.Popen() 从 bash shell 转换为 python3

Question

我正在努力从 bash shell 转换为 python3。

这是我想转换为 python 的 shell 命令:

cat $outDir/aDir/* | cut -f2 | sort -u > $outDir/outFile.txt

我已经使用了 subprocess.call()并且它有效，但我想知道如何使用 Popen() 实现它。

这是我的代码，但没有用:

import subprocess
import glob

filePath = outDir + 'aDir/*'
outFilePath = outDir + '/outFile.txt'

fileList = []
for files in glob.glob(filePath):
    fileList.append(files)
with open(files, 'r') as inFile, open(outFilePath, 'w') as outFile : 
  p = subprocess.Popen(['cat'], stdin=inFile, stdout=subprocess.PIPE)   
  p2 = subprocess.Popen(['cut', '-f2'], stdin = p1.stdout, stdout=subprocess.PIPE)
  p3 = subprocess.Popen(['sort', '-u'], stdin = p2.stdout, stdout = outFile)

您能解释一下为什么 shell=True 有害吗？我在很多答案中看到它，但不知道为什么...

谢谢。

Answer 1

您需要将文件列表传递给 cat所以

subprocess.Popen(['cat'], stdin=inFile, stdout=subprocess.PIPE)

应该变成

subprocess.Popen(['cat'] + [fileList], stdout=subprocess.PIPE)

因此不再需要 inFile

总而言之

import subprocess
import glob

filePath = outDir + '/aDir/*'
outFilePath = outDir + '/outFile.txt'

fileList = glob.glob(filePath)
with open(outFilePath, 'w') as outFile: 
  subprocess.Popen(['cat'] + [fileList], stdout=subprocess.PIPE)
  p2 = subprocess.Popen(['cut', '-f2'], stdin = p1.stdout, stdout=subprocess.PIPE)
  p3 = subprocess.Popen(['sort', '-u'], stdin = p2.stdout, stdout = outFile)