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python - 在 Telegram 的 TL 模式语言中处理 "flags"类型

转载 作者:太空宇宙 更新时间:2023-11-04 03:08:10 25 4
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我写了一个 tl 解析器,所以现在可以使用最新的层 (53)。但我不确定如何处理“标志”类型。它们仅在 tl 文档中提及,但未在此处页面底部定义(据我所知):link .

例如,当方法返回“消息”类型时,它应该如下所示: message#c09be45f flags:# out:flags.1?true mentioned:flags.4?true media_unread:flags.5?true silent:flags.13?true post:flags.14?true id:int from_id:flags.8?int to_id:Peer fwd_from:flags.2?MessageFwdHeader via_bot_id:flags.11?int reply_to_msg_id:flags.3?int date:int message:string media:flags.9?MessageMedia reply_markup:flags.6?ReplyMarkup entities:flags.7?Vector<MessageEntity> views:flags.10?int edit_date:flags.15?int = Message;

如果我理解正确,每个标志位都设置在某个变量中,对吧?

我的解析器像这样分解“消息”类型:

     id: -1063525281
params:
name: flags
type:
name: out
bit: 1
type: true

name: mentioned
bit: 4
type: true

name: media_unread
bit: 5
type: true

name: silent
bit: 13
type: true

name: post
bit: 14
type: true

name: from_id
bit: 8
type: int

name: fwd_from
bit: 2
type: MessageFwdHeader

name: via_bot_id
bit: 11
type: int

name: reply_to_msg_id
bit: 3
type: int

name: media
bit: 9
type: MessageMedia

name: reply_markup
bit: 6
type: ReplyMarkup

name: entities
bit: 7
type: Vector<MessageEntity>

name: views
bit: 10
type: int

name: edit_date
bit: 15
type: int

name: id
type: int

name: to_id
type: Peer

name: date
type: int

name: message
type: string

predicate: message
type: Message

但是如果标志是某个变量中的位,哪个变量?

相关:tl 是基于正式的、标准化的语言规范还是专门为 Telegram 创建的?我问是因为如果它是正式语言(如 yaml)的子集,那么最好使用已知的 tl 解析器而不是重新发明轮子。

最佳答案

But if the flags are bits in some variable, which variable?

Message#c09be45f flags:# out:flags.1?true mentioned:flags.4?true media_unread:flags.5?true silent:flags.13?true post:flags.14?true id:int from_id:flags.8?int to_id:Peer fwd_from:flags.2?MessageFwdHeader via_bot_id:flags.11?int reply_to_msg_id:flags.3?int date:int message:string media:flags.9?MessageMedia reply_markup:flags.6?ReplyMarkup entities:flags.7?Vector<MessageEntity> views:flags.10?int edit_date:flags.15?int = Message;

示例:flags:# out:flags.1?true

解码标志:BinaryAND(flags, 2^ix) === 2^ix --> 这将帮助您确定是否包含某个字段

flags = flags 字段的值,这通常是带有标志的对象的第一个字段

ix == flag index,这是一个表示标志位置的数字,例如out:flags.1?true这里out是flag位置1的字段,类型为true

对于上面的示例,如果 BAND(flags,2^N) == 2^Nout 的值为 true 否则, out 字段被忽略

代码 - 消息编码(Elixir)

def encode(%Message{} = x), do: <<95, 228, 155, 192, encode(:Int, x.flags)::binary, enc_f(:True, x.out, x.flags, 2)::binary, enc_f(:True, x.mentioned, x.flags, 16)::binary, enc_f(:True, x.media_unread, x.flags, 32)::binary, enc_f(:True, x.silent, x.flags, 8192)::binary, enc_f(:True, x.post, x.flags, 16384)::binary, encode(:Int, x.id)::binary, enc_f(:Int, x.from_id, x.flags, 256)::binary, encode(x.to_id)::binary, enc_f(x.fwd_from, x.flags, 4)::binary, enc_f(:Int, x.via_bot_id, x.flags, 2048)::binary, enc_f(:Int, x.reply_to_msg_id, x.flags, 8)::binary, encode(:Int, x.date)::binary, encode(:String, x.message)::binary, enc_f(x.media, x.flags, 512)::binary, enc_f(x.reply_markup, x.flags, 64)::binary, enc_vf(x.entities, x.flags, 128)::binary, enc_f(:Int, x.views, x.flags, 1024)::binary, enc_f(:Int, x.edit_date, x.flags, 32768)::binary>>

代码 - 消息解码(Elixir)

  def decode(<<95, 228, 155, 192, bin::binary>>) do
{flags, bin} = decode(:Int, bin)
{out, bin} = decode(:True, bin, flags, 2) # 1
{mentioned, bin} = decode(:True, bin, flags, 16) # 4
{media_unread, bin} = decode(:True, bin, flags, 32) # 5
{silent, bin} = decode(:True, bin, flags, 8192) # 13
{post, bin} = decode(:True, bin, flags, 16384) # 14
{id, bin} = decode(:Int, bin)
{from_id, bin} = decode(:Int, bin, flags, 256) # 8
{to_id, bin} = decode(bin)
{fwd_from, bin} = decode(bin, flags, 4) # 2
{via_bot_id, bin} = decode(:Int, bin, flags, 2048) # 11
{reply_to_msg_id, bin} = decode(:Int, bin, flags, 8) # 3
{date, bin} = decode(:Int, bin)
{message, bin} = decode(:String, bin)
{media, bin} = decode(bin, flags, 512) # 9
{reply_markup, bin} = decode(bin, flags, 64) # 6
{entities, bin} = decode([:MessageEntity], bin, flags, 128) # 7
{views, bin} = decode(:Int, bin, flags, 1024) # 10
{edit_date, bin} = decode(:Int, bin, flags, 32768) # 15
{%Message{flags: flags, out: out, mentioned: mentioned, media_unread: media_unread, silent: silent, post: post, id: id, from_id: from_id, to_id: to_id, fwd_from: fwd_from, via_bot_id: via_bot_id, reply_to_msg_id: reply_to_msg_id, date: date, message: message, media: media, reply_markup: reply_markup, entities: entities, views: views, edit_date: edit_date}, bin}
end

#5 == 2^5 == 32
#4 == 2^4 == 16

所以基本上 N == 2^N,其中 N == ix

关于python - 在 Telegram 的 TL 模式语言中处理 "flags"类型,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/38903321/

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