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python - 库达 API 错误 : [1] Call to cuLaunchKernel results in CUDA_ERROR_INVALID_VALUE in Python

转载 作者:太空宇宙 更新时间:2023-11-04 03:06:24 33 4
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尝试使用 CUDA 在 Python 中运行此代码时出现此错误。我正在学习本教程,但我正在 Windows 7 x64 机器上尝试它。

https://www.youtube.com/watch?v=jKV1m8APttU

事实上,我运行了 check_cuda() 并且所有测试都通过了。任何人都可以帮助我这里的确切问题是什么。

我的代码:

import numpy as np
from timeit import default_timer as timer
from numbapro import vectorize, cuda

@vectorize(['float64(float64, float64)'], target='gpu')
def VectorAdd(a, b):
return a + b

def main():
N = 32000000

A = np.ones(N, dtype=np.float64)
B = np.ones(N, dtype=np.float64)
C = np.zeros(N, dtype=np.float64)

start = timer()
C = VectorAdd(A, B)
vectoradd_time = timer() - start

print("C[:5] = " + str(C[:5]))
print("C[-5:] = " + str(C[-5:]))

print("VectorAdd took %f seconds" % vectoradd_time)

if __name__ == '__main__':
main()

错误信息:

---------------------------------------------------------------------------
CudaAPIError Traceback (most recent call last)
<ipython-input-18-2436fc2ab63a> in <module>()
1 if __name__ == '__main__':
----> 2 main()

<ipython-input-17-64de53fdbe77> in main()
7
8 start = timer()
----> 9 C = VectorAdd(A, B)
10 vectoradd_time = timer() - start
11

C:\Anaconda2\lib\site-packages\numba\cuda\dispatcher.pyc in __call__(self, *args, **kws)
93 the input arguments.
94 """
---> 95 return CUDAUFuncMechanism.call(self.functions, args, kws)
96
97 def reduce(self, arg, stream=0):

C:\Anaconda2\lib\site-packages\numba\npyufunc\deviceufunc.pyc in call(cls, typemap, args, kws)
297
298 devarys.extend([devout])
--> 299 cr.launch(func, shape[0], stream, devarys)
300
301 if any_device:

C:\Anaconda2\lib\site-packages\numba\cuda\dispatcher.pyc in launch(self, func, count, stream, args)
202
203 def launch(self, func, count, stream, args):
--> 204 func.forall(count, stream=stream)(*args)
205
206 def is_device_array(self, obj):

C:\Anaconda2\lib\site-packages\numba\cuda\compiler.pyc in __call__(self, *args)
193
194 return kernel.configure(blkct, tpb, stream=self.stream,
--> 195 sharedmem=self.sharedmem)(*args)
196
197 class CUDAKernelBase(object):

C:\Anaconda2\lib\site-packages\numba\cuda\compiler.pyc in __call__(self, *args, **kwargs)
357 blockdim=self.blockdim,
358 stream=self.stream,
--> 359 sharedmem=self.sharedmem)
360
361 def bind(self):

C:\Anaconda2\lib\site-packages\numba\cuda\compiler.pyc in _kernel_call(self, args, griddim, blockdim, stream, sharedmem)
431 sharedmem=sharedmem)
432 # Invoke kernel
--> 433 cu_func(*kernelargs)
434
435 if self.debug:

C:\Anaconda2\lib\site-packages\numba\cuda\cudadrv\driver.pyc in __call__(self, *args)
1114
1115 launch_kernel(self.handle, self.griddim, self.blockdim,
-> 1116 self.sharedmem, streamhandle, args)
1117
1118 @property

C:\Anaconda2\lib\site-packages\numba\cuda\cudadrv\driver.pyc in launch_kernel(cufunc_handle, griddim, blockdim, sharedmem, hstream, args)
1158 hstream,
1159 params,
-> 1160 None)
1161
1162

C:\Anaconda2\lib\site-packages\numba\cuda\cudadrv\driver.pyc in safe_cuda_api_call(*args)
220 def safe_cuda_api_call(*args):
221 retcode = libfn(*args)
--> 222 self._check_error(fname, retcode)
223
224 setattr(self, fname, safe_cuda_api_call)

C:\Anaconda2\lib\site-packages\numba\cuda\cudadrv\driver.pyc in _check_error(self, fname, retcode)
250 errname = ERROR_MAP.get(retcode, "UNKNOWN_CUDA_ERROR")
251 msg = "Call to %s results in %s" % (fname, errname)
--> 252 raise CudaAPIError(retcode, msg)
253
254 def get_device(self, devnum=0):

CudaAPIError: [1] Call to cuLaunchKernel results in CUDA_ERROR_INVALID_VALUE

最佳答案

我通过 NVIDIA 开发者论坛找到了解决我的问题的方法。如果您想了解有关该解决方案的更多信息,请查看此链接。

https://devtalk.nvidia.com/default/topic/962843/cuda-programming-and-performance/cudaapierror-1-call-to-culaunchkernel-results-in-cuda_error_invalid_value-in-python/?offset=3#4968130

简而言之:

  • 当我更改 N = 32000 或任何其他更小的数量时,它确实运行良好。
  • 事实上,这意味着我没有以正确的 GPU 类型编译它(check_cuda 是验证它的函数调用)。

希望我的回答对大家有所帮助。

关于python - 库达 API 错误 : [1] Call to cuLaunchKernel results in CUDA_ERROR_INVALID_VALUE in Python,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/39323256/

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