javascript - NodeJS 循环内部包含异步函数

Question

我遇到的问题是 for(var x=1; x < 6; x++)因为速度太快而被调用 axios.get()是异步的，但我不知道如何在解决方案过于复杂的情况下解决这个问题

const axios = require("axios");
const cheerio = require("cheerio");

function imdbGetData(id) {
  var title, show, $;
  var arr = [];
  var airdates = [];
  show = {
    seasons: []
  };

  axios.get(`http://www.imdb.com/title/${id}/`).then((body) => {
    $ = cheerio.load(body.data);
    title = $("div h1").text()
  });
  for(var x=1; x < 6; x++) {
    console.log(x); // Will count too 1,2,3,4,5,6
    url = `http://www.imdb.com/title/${id}/episodes?season=${x}`
    axios.get(url).then((body) => {
      $ = cheerio.load(body.data);
      console.log(x);// 6, 6, 6, 6
      $("div .info .airdate").each(function(index, item) {
        var airdate = String($(this).text());
        airdates.push(airdate.trim());
      });


      $(".info strong a").each(function(i, item){
          var airdate = airdates[i];

          var epsiode_name = $(this).text()
          if (epsiode_name && !epsiode_name.includes("#"))
            arr.push({epsiode_name, airdate});
      });
      show.seasons.push(arr);
      arr = []
      // console.log(show.seasons);
    });
    setTimeout(() => {console.log(show.seasons)}, 10000) // ghetto
  }
}

// season = {
//   seasons: [[ {epsiode_name} ], [{Epsiode name}]]
// }

imdbGetData("tt2193021");

Answer 1

您可以构造所有 Promise 并将其推送到数组，然后使用 Promise.all(arrayOfPromises)。这样，您将保留异步链，并且可以轻松处理与常规单个异步操作非常相似的结果:

var promises = [];
for (var x = 1; x < 6; x++) {
  url = `http://www.imdb.com/title/${id}/episodes?season=${x}`
  promises.push(axios.get(url));
}

Promise.all(promises)
  .then(body => {
    // all results of promises will be in 'body' parameter
  })
  .catch(err => console.error(err));