python - Django int() 参数必须是字符串、类字节对象或数字，而不是 'QueryDict'

Question

我有一个显示表单并保存相同表单的 View 。显示 View 没有问题，但保存时出现以下错误:

int() 参数必须是字符串、类字节对象或数字，而不是“QueryDict”

这是我的代码:

型号:

class Category(models.Model):
    name = models.CharField(max_length=100, db_index=True, unique=True)
    slug = models.SlugField(max_length=100, db_index=True, unique=True)
    user = models.ForeignKey(User, related_name='categories')

    class Meta:
        ordering = ('name',)
        verbose_name = 'category'
        verbose_name_plural = 'categories'

    def __str__(self):
        return self.name

    def save(self, *args, **kwargs):
        if not self.slug:
            self.slug = slugify(self.name)
            super(Category, self).save(*args, **kwargs)

    def get_absolute_url(self):
        return reverse('wallet:category_details', args=[self.id])

View :

@login_required
def category_create(request):
    user = request.user
    if request.method == 'POST':
        category_create_form = CategoryCreateForm(request.POST)
        if category_create_form.is_valid():
            new_category = category_create_form.save(commit=False)
            new_category.user = request.user
            new_category.save()
            return render(request, 'category/done.html')
    else:
        category_create_form = CategoryCreateForm()
    return render(request, 'category/create.html', {'category_form': category_create_form})

表格:

class TransactionCreateForm(forms.ModelForm):
    field_order = ['name', 'type', 'wallet', 'category', 'date', 'amount', 'notes', ]

    class Meta:
        model = Transaction
        fields = ('name', 'type', 'wallet', 'category', 'date', 'amount', 'notes',)

    def __init__(self, user, *args, **kwargs):
        super(TransactionCreateForm, self).__init__(*args, **kwargs)
        self.fields['wallet'] = forms.ChoiceField(
        choices=[(wallet, str(wallet)) for wallet in Wallet.objects.filter(user=user)])

我该如何解决？

Answer 1

您的表单的 __init__ 方法指定了一个 user 参数，您在实例化它时没有提供该参数。创建您的表单:

category_create_form = CategoryCreateForm(user)

或者，在 POST 分支中，

category_create_form = CategoryCreateForm(user, request.POST)

好吧，假设实际类看起来像您发布的不同名称的表单类。基本上，看看您的表单需要哪些参数。