c - 将字符串读入 char 数组，然后获取字符串的大小

Question

我正在做一个项目，但我对这部分感到困惑。

我需要从 stdin 读取单词并将它们放在一个 char 数组中，并使用一个指针数组指向每个单词，因为它们会呈锯齿状。其中 numwords 是一个代表字数的整数。

    char words[10000];
    char *wordp[2000];

问题是我只能使用指针来添加单词。我不能再使用 [] 来帮助了。

    *wordp = words; //set the first pointer to the beginning of the char array. 
    while (t < numwords){
      scanf("%s", *(wordp + t))  //this is the part I dont know
      wordp = words + charcounter; //charcounter is the num of chars in the prev word
      t++;
    }

    for(int i = 0;words+i != '\n';i++){
      charcounter++;
    }

任何帮助都会很棒我对指针和数组很困惑。

Answer 1

如果您使用额外的指针，您的代码将更易于管理直接引用并增加它。这样你就不必做任何事情心理数学。此外，您需要在递增引用之前读取下一个字符串时，scanf 不会为您移动指针。

char buffer[10000];
char* words[200];

int number_of_words = 200;
int current_words_index = 0;

// This is what we are going to use to write to the buffer
char* current_buffer_prt = buffer;

// quick memset (as I don't remember if c does this for us)
for (int i = 0; i < 10000; i++)
    buffer[i] = '\0';

while (current_words_index < number_of_words) {

    // Store a pointer to the current word before doing anything to it
    words[current_word_index] = current_buffer_ptr;

    // Read the word into the buffer
    scanf("%s", current_buffer_ptr);

    // NOTE: The above line could also be written
    // scanf("%s", words[current_word_index]);

    // this is how we move the buffer to it's next empty position.
    while (current_buffer_ptr != '\n') 
        current_buffer_ptr++;

    // this ensures we don't overwrite the previous \n char
    current_buffer_ptr++;

    current_words_index += 1;
}