c - Monty hall show模拟出乎意料的结果

Question

#include <stdio.h>
#include <time.h>

int main (void)
{
    int pickedDoor, remainingDoor, hostDoor, winningDoor, option, games = 0, wins = 0;

    float frequency = 0;

    srand (time(NULL));


  while (1)
    {
        printf ("Pick one of the three doors infront of you, which do you want?\n");
        scanf ("%d", &pickedDoor);

        if (pickedDoor > 3 || pickedDoor <= 0)
        {
            break;
        }

        winningDoor = rand() % 3 + 1;


        do
        {
            hostDoor = rand() % 3 + 1;
        } while (hostDoor == pickedDoor || hostDoor == winningDoor);

        do
        {
            remainingDoor = rand() % 3+1;
        } while (remainingDoor == pickedDoor || remainingDoor == hostDoor);

        printf ("The door the host picked is %d\n", hostDoor);
        do
        {
        printf("Do you want to switch doors? Please enter in the door you want:\n", hostdoor);
        scanf("%d", &option);
       if (option > 3 || option <= 0)
         {return 0;}
        }while (option == hostDoor);


        if (option == winningDoor)
        {
            printf("You Won!\n");
            wins++;
        }

        else 
        {
            printf("YOU LOSE!\n");
        }

        games++;
    }

    frequency = ((float) wins / games) *100;

    printf ("The number of games that you won is %d\n", wins);

    printf ("The frequency of winning is %.0f%%\n", frequency);

    return 0;
}

嗨，这是我的 monty hall 游戏秀版本，不过我得到了意想不到的结果。

有时，当我进入一扇门进行选择时，它只会让我回到“从你面前的三扇门中选择一扇”的语句，此时它应该告诉我我是赢了还是输了。

我认为这是因为“选项”门等于“主机门”。

我认为使用“option != hostDoor”可以解决问题，但事实并非如此。

如果我的假设是正确的，我该如何解决？如果不是，为什么它不起作用，我该如何解决？

Answer 1

为了正确模拟，OP 需要显示主机门。

do {
  printf("Do you want to switch doors? Please enter in the door you want:\n");
  scanf("%d", &option);
  if (option > 3 || option <= 0 ) {
    return 0;
    }
  } while (option == hostDoor);

// instead of 
#if 0
printf("Do you want to switch doors? Please enter in the door you want:\n");
scanf("%d", &option);
if (option > 3 || option <= 0 ) { return 0; }
#endif

---

处理 OP “它应该告诉我我是赢了还是输了。”问题，改变

else if (option == remainingDoor)

到

else

---

您的 scanf("%d", &option) 没问题。我更喜欢 fgets()/sscanf() 组合，它对于检查 scanf() 系列的结果总是很有用，但这不是你的问题。