python - termcolor python 中的占位符

Question

我正在处理 CS50 的情绪挑战，我想使用 Termcolor 和占位符在控制台中打印颜色，但我遇到了一些问题。

这是我的代码:

    if score > 0:
        green = lambda x: colored(x, 'green')
        print(green("1 ", tweets))
    elif score < 0:
        red = lambda x: colored(x, 'red')
        print(red(tweets))
    else:
        yellow = lambda x: colored(x, 'yellow')
        print(yellow(tweets))

我想根据分数(绿色、红色或黄色)打印推文，这没关系，代码适用于 lambda x，但我还想在推文之前以相同颜色打印数字。

我试过 lambda x, y 但我有一个错误:

if score > 0:
   green = lambda x, y: colored(x, y, 'green')
   print(green("1 ", tweets))


Traceback (most recent call last):
File "./tweets", line 47, in <module>
  main()
File "./tweets", line 39, in main
  print(green("1 ", tweets))
File "./tweets", line 38, in <lambda>
  green = lambda x, y: colored(x, y, 'green')
File "/usr/lib/python3/dist-packages/termcolor.py", line 105, in colored
text = fmt_str % (COLORS[color], text)
  KeyError: 'Building Augmented Reality Experiences with Unity3D (and @Microsoft @HoloLens)  by @shekitup at @CS50 at @Harvard,'

这是我要打印的内容:

1 + (tweets) in green if positive
-1 + (tweets) in red if negative
0 + (tweets) in yellow if neutral

Answer 1

您可以创建一个子任务并调用它:

def show_tweets_by_color(num, col, tweets):
  green = lambda x: colored(x, 'green')
  print(colored(str(num), " green") + green(tweets))


if score > 0:
    show_tweets_by_color(1, "green", tweets)
...