c - 将字符串扫描成结构

Question

在文本文件中，第一个数字是专辑的数量，第二个是与单个专辑关联的轨道的数量，每个轨道标题前面的数字是标题的字符长度。

现在我无法将每个标题的名称(前面没有数字)扫描到 char **tracks; 中，它也是结构数组的一部分

例如，info[0].tracks[0] 应该打印出字符串“Like an umbrella”。

示例文本文件:

1
17
16 Like an umbrella
...
15 Dynasty Warrior

代码:

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

struct album 
{
     int num_tracks;
     char **tracks;

};

int main(int argc, char *argv[]){
int numbALBUMS=0, numbCharInTrack=0;
int i=0,j=0;

    FILE *albums;
    albums = fopen (argv[1], "r");

    fscanf(albums, "%d", &numbALBUMS);
    struct album *info = (struct album*)malloc(numbALBUMS * sizeof(struct album));

    for(i=0;i<numbALBUMS;i++){
        fscanf(albums, "%d", &info[i].num_tracks);
        info[i].tracks = malloc(sizeof(char*) * info[i].num_tracks);

            for(j=0;j<info[i].num_tracks;j++){
                fscanf(albums, "%d", &numbCharInTrack);
                info[i].tracks[j] = malloc(sizeof(char) * numbCharInTrack);

                //NEED HELP HERE

            }
    }


fclose(albums);
return 0;

}

Answer 1

试试这个

fscanf(albums, "%d", &numbCharInTrack);
info[i].tracks[j] = malloc(sizeof(char) * (numbCharInTrack+1));//+1 for NUL, sizeof(char) is always 1(by standard)
fscanf(albums, " %[^\n]", info[i].tracks[j]);//Space to skip the previous space